7.14 For a normally consolidated clay, the following values are given: Void ratio, e k (cm/sec) 0.95 0.2 x 10-6 0.91 x 10-6 1.6 Estimate k at a void ratio of 1.1. Use Eq. (7.38). ⒸCengage Learning 2014

Q: Laboratory consolidation tests were conducted on a specimen collected from the middle of the clay…

A: The results of the field consolidation curve are interpolated from the laboratory test results.The…

Q: A normally consolidated clay has the following values void ratio e = 1.2, k(cm/sec) = 0.2 x 10^-6…

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Q: Refer to the soil profile shown in figure below. A laboratory consolidati the results: o'c = 100 kPa…

A: Dry unit weight of sand γdsand=Gγw1+e=2.669.811+0.55=16.835kNm3Sat unit weight of sand…

Q: Question Attached

A: Principal Stress shows the maximum normal stress principal stresses are the maximum and minimum…

Q: For a clay layer in the field, the following are given: H = 7.5' Po = 0.7 ton/ft2 Po + AP = 2.5…

A: Given data in question  Initial void ratio Depth Stress Overburden stress Graph on semi log scale To…

Q: Table 1 given below presents the results of a conventional oedometer consolidation test conducted on…

A: The compressibility of the soil takes place in two different methods namely consolidation and…

Q: A CU triaxial test was carried out on a silty clay that was isotopically consolidated using a cell…

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Q: Estimate the consolidation settlement of the clay layer shown in Figure P6.8 using the results of…

A: The step by step solution is given below.

Q: 2 A 2-m clay layer in the field has a current effective stress, o6= 70 kN/m². There is a net stress…

A: 2 m clay layer effective stress = 70 N/mm2 net increse stress = 180 kN/mm2 primary consolidation =?…

Q: SIT S. The results of two-drained tri-axial tests on a saturated clay are recorded as follows:…

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Q: The relationship between the relative density, Dr, and the angle of friction, phi prime, of a sand…

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Q: Sample description: Uniform SAND, medium grain. Rate of strain: 1 mm/min Proving Ring No. ==…

A: Time (min) Horiz. Displ. (mm) Strain (%) Proving ring Dial (rev) Shear Load (N) Shear Stress (kPa)…

Q: 4. For a normally consolidated clay, the following values are given. k (cm/sec) 0.45 x 10 e 0.78 1.1…

A: For e = 0.78, k = 0.45×10-6 and for e = 1.1, k = 0.88×10-6 we have to find k at void ratio e =0.97

Q: Problem 3: A layered soil is shown below. Given: H1 = 1.5 m kj = 9 x 104 cm/sec H2 = 2.5 m k2 =7.8 x…

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Q: Ex (21) The shear strength equation of a compacted soil can be expressed as (S=Tf= 9.6+5 tan 30).…

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Q: clay layer having a thickness of 10.83 m. has an initial void ratio of 1.14. It is compressed and…

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Q: Following results were recorded from a consolidation test on a specimen of saturated clay, each load…

A: After subjecting a saturated clay specimen to a consolidation test, each load was held constant for…

Q: Q-2: Following are the results of four drained direct shear tests on an over consolidated clay:…

A: Diameter = 50 mm  Height = 25 mm

Q: 8.2 The results of a laboratory consolidation test on a clay sample are given below. Pressure, o…

A: Given:- The results of a laboratory consolidation test on a clay sample are given below.

Q: For a laboratory consolidation test on a clay specimen (drained on both sides) the following results…

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Q: 2. The following results were obtained from an oedometer test on a specimen of saturated clay:…

A: From the given question it is required to determine the final settlement due to consolidation of the…

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.