2. The following results were obtained from an oedometer test on a specimen of saturated clay: Pressure (kN/m²) 27 54 107 214 429 214 107 54 Void ratio 1.243 1.217 1.144 1.068 0.994 1.001 1.012 1.024 A layer of this clay 8m thick lies below a 4m depth of sand, the water table being at the surface. The saturated unit weight for both soils is 19kN/m3. A 4m depth of fill of unit weight 21 kN/m3 is placed on the sand over an extensive area. Determine the final settlement due to consolidation of the clay.

2. The following results were obtained from an oedometer test on a specimen of saturated clay: Pressure (kN/m²) 27 54 107 214 429 214 107 54 Void ratio 1.243 1.217 1.144 1.068 0.994 1.001 1.012 1.024 A layer of this clay 8m thick lies below a 4m depth of sand, the water table being at the surface. The saturated unit weight for both soils is 19kN/m3. A 4m depth of fill of unit weight 21 kN/m3 is placed on the sand over an extensive area. Determine the final settlement due to consolidation of the clay.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: A simple of dry sand is subjected to a triaxial test. During the test if deviator stress and cell…

Q: A sample of dry sand having a unit weight of 16.50 kN/m3 and a specific gravity of 2.7 is placed in…

A: Dry unit weight = 16.50KN/m3 Specific gravity = 2.7 Saturation after Rain Sr =0.40

Q: The volume and weight of a partially saturated clay sample are 185 cm3 and 362 g respectively. After…

Q: The dry density of a sand with porosity of 0.37 is 1.61 Mg/m. Calculate the void ratio of the soil:…

A: Introduction : In this question we have to determine the value of void ratio . Void ratio is defined…

Q: A normally consolidated clay sample, which is fully saturated, was consolidated in the triaxial cell…

A: Given data- A normally consolidated clay sample. ½ (σ1 – σ3) = 1/3 σ3 and ½ (σ1′ + σ3′) = 2/3 σ'3…

Q: 9. A cubic meter of a saturated, normally consolidated clay has a dry mass of 4 kg and a porosity of…

A: Since we know that Void ratio (e) = Porosity1- porosity = n1-n Here porosity (n) =…

Q: A saturated 100cm^3 clay sample has a natural water content of 30% . It is found that the shrinkage…

A: Use formula of shrinkage limit Ws=1/R - 1/G

Q: 2.9 A normally consolidated clay has the following values. Void ratio, e k (cm/sec) 0.2 x 10 0.91 X…

A: void ratio and permeability of a soil medium can be related to each other as follows…

Q: A 600 cm volume of moist sand weighs 1050 g Its dry weight is 930 g and specific gravity of solids,…

A: Given:- The volume of the moist sand = 600 cm3 The weight of the moist sand = 1050 g The weight of…

Q: Question B1a: A soil is assumed to obey Hook's law with the shear modulus G =8500 kPa and Poisson's…

A: Step 1

Q: A clay layer of thickness 10 cm and initial void ratio 0.5 undergoes settlement so that the final…

A: Given that :- Thickness of clay deposit = Ho=10 cm Initial void ratio = eo= 0.5 Final void ratio = e…

Q: A wet sand sample has a volume of 4.64 x 10⁻⁴ and weighs 8N. After oven drying, the weight reduces…

A: As per guidelines we need to answer only first question so please repost rest questions separately.…

Q: A clay has the following Atterberg limits: liquid limit 6x% and plastic limit = 35. у%, a. Determine…

A: Given Liquid limit, LL = 62 % Plastic limit, PL = 35.5 % To Determine Plasticity Index of the…

Q: The maximum and minimum void ratios for a sand are 0.805 and 0.501 respectively. The field density…

A: Given : Maximum void ratio for sand = 0.805 Min. void ratio for sand = 0.501 density = 1.81 Mg/m3 w…

Q: 4. In a consolidated-drained triaxial test on a clay that is normally consolidated, the results are…

Q: The data of soil specimen are given below; Y(pcf) = 128.9, S% = 48.7 Y(pcf) = 131.4, S% = 78.8 a.…

A: We know Y= (G+Se)(1+e)Yw When Y=128.9, S=48.7% And when Y=131.4, S=78.8%

Q: a wet sand sample has a volume of 4.6 x 10^-4 m^3 and weighs 8.1 N. After oven-drying, the weight…

Q: Q3) A normally consolidated clay has the following values: Estimate the magnitude of k of the clay…

A: It is the ability of the soil to allow water to pass through the void space of the soil. The clay…

Q: A clay soil, tested in a consolidometer showed a decrease in void ratio from 1.20 to 1.10 when the…

Q: soil mechanics Q1- he mass of a moist soil sample collected from the field is 465 grams, and its…

A: given mass of moist soil sample =465gm mass of oven dried sample=405.76gm specific gravity of the…

Q: clay layer having a thickness of 10.83 m. has an initial void ratio of 1.14. It is compressed and…

Q: A consolidated-drained triaxial test was conducted on sand. The results are as follows: Confined…

A: Using formula to get internal friction angle

Q: The porosity of the soil will be 1 1N. 13

A: SOIL MECHANICS:

Concept explainers

Sediment transport

Sediment transport or Soil transport is the movement of solid particles, usually due to the combination of gravitational forces acting on the sediment, and the movement of the liquid at which the sediment enters. Soil erosion occurs in natural systems where the particles are sandstones (sand, rocks), mud, or clay; the liquid is air, water, or ice; and the gravitational force that works to move particles to the landing surface. Sediment transportation or soil migration due to the movement of liquids occurs in rivers, lakes, lakes, oceans, and other bodies of water as a result of currents and waves. Transportation is also caused by glaciers as they flow, and to places on earth under the influence of wind. Soil erosion due to gravity alone is possible in most sloping areas, including hills, scarves, cliffs, and the continental shelf — the continental boundary of the slope.

Question

Homeworks
2. The following results were obtained from an oedometer test on a specimen
of saturated clay:
Pressure (kN/m?) 27
54
107 214 429 214 107 54
Void ratio
1.243 1.217 1.144 1.068 0.994 1.001 1.012 1.024
A layer of this clay 8m thick lies below a 4m depth of sand, the water table
being at the surface. The saturated unit weight for both soils is 19kN/m3. A
4m depth of fill of unit weight 21 kN/m3 is placed on the sand over an
extensive area. Determine the final settlement due to consolidation of the
clay.
-1
e -eo
1+e, o'y-o'vo
my
S =
i=l

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

A consolidated-drained triaxial test was conducted on a normally consolidated clay. The results are as follows: • 03 = 16 lb/in. • (Aoa) = 25 lb/in. Determine a. Angle of friction, d'
A soil specimen has a volume of 0.05 m³ and a mass of 87.5 kg. Given: w= 15%, G,= 2.68. Determine a. Void ratio
A sample of saturated clay was placed in a container and weighed. The weight was 6N. The clay in its container was placed in an oven for 24 hours at 105˚C. The weight reduced to a constant value of 5N. The weight of the container is 1N. If Gs = 2.7, determine: a) Water Content b) Void Ratio c) Bulk Unit Weight d) Dry Unit Weight e) Effective Unit Weight
A certain saturated sand (S = 100%) has a moisture content of 27.9% and a specific gravity of solids of 2.61. It also has a maximum index void ratio of 0.90 and a minimum index void ratio of 0.33. Compute its relative density and classify its consistency. (Table on the right) Solution: Given the values of mmoisture content, specific gravity and degree of saturation, the void ratio can be estiamted as: e = Thus the relative density is found to be Dr = • According to the table, the soil is classified as %; soil. TABLE 3.3 CONSISTENCY OF COARSE-GRAINED SOILS AT VARIOUS RELATIVE DENSITIES (data from Lambe and Whitman, 1969) Relative Density, D,(%) 0-15 15-35 35-65 65-85 85-100 Classification Very loose Loose Medium denseª Dense Very dense "Lambe and Whitman used the term "medium," but "medium dense" is better because "medium" usually refers to the particle size distribution.
7.14 For a normally consolidated clay, the following values are given: Void ratio, e k (cm/sec) 0.95 0.2 x 10-6 0.91 x 10-6 1.6 Estimate k at a void ratio of 1.1. Use Eq. (7.38). Ⓒ Cengage Learning 2014
The normal stress of a soil sample is165 kPa at void ratio of 0.66. If the compression index of the soil is 0.25, determine the normal stress on the soil at void ratio of 0.56
5. A sand sample having specific gravity of 2.7 has a saturated unit weight of 20 KN/ m3. What is the void ratio of the sample? A. 0.54 B. 0.69 C. 0.64 D. 0.77
A Sample of Clay is isotropically normally consolidated to a cell pressure of 350kPa. The sample was then sheared (standard) in a drained state. Calculate values of q, p', and v at failure if the soil constants were: M=0.88, N=2.88, I-2.76, and 2-0.16
The porosity (n) of a mass of soil is 46.69 %. What is the void ratio, e, expressed as a percentage? Lütfen birini seçin: O a. 114% O b. 53.31% O c. 87.58% O d. 31.83%