A 1.10-in.-diameter solid shaft is subjected to an axial force of P = 3300 lb, a horizontal shear force of V = 510 lb, and a concentrated torque of T= 1250 lb-in., acting in the directions shown. Assume L= 6.6 in. Section properties for the shaft areA= 0.9503 in.?, J= 0.1437 in.“, ly=lz= 0.0719 in.“, and Q = 0.1109 in.3. Determine the normal and shear stresses at point K, and show these stresses on a stress element.

A 1.10-in.-diameter solid shaft is subjected to an axial force of P = 3300 lb, a horizontal shear force of V = 510 lb, and a concentrated torque of T= 1250 lb-in., acting in the directions shown. Assume L= 6.6 in. Section properties for the shaft areA= 0.9503 in.?, J= 0.1437 in.“, ly=lz= 0.0719 in.“, and Q = 0.1109 in.3. Determine the normal and shear stresses at point K, and show these stresses on a stress element.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Methods to Determine Vertical Stress

The load applied to the soil is transferred to the underground. The presence of water at soil pores and solid grains above the soil are the primary components that are responsible for the effective load transfer. Due to the load acting, the internal component of the soil or the underground formations undergoes deformations or a tectonic shift. The amount of deformation depends upon the amount of load acting on the soil surface, which indeed, depends on the weight of everything present above the soil. Due to this, the underground soil element develops internal stresses which try to resist the tectonic changes.

Question

A 1.10-in.-diameter solid shaft is subjected to an axial force of P = 3300 Ib, a horizontal shear force of V = 510 lb, and a concentrated
torque of T = 1250 lb-in., acting in the directions shown. Assume L = 6.6 in. Section properties for the shaft are A = 0.9503 in.?, J =
0.1437 in.“, ly= 1z = 0.0719 in.“, and Q = 0.1109 in.3. Determine the normal and shear stresses at point K, and show these stresses on a
stress element.
y
K
T
V
Answer:
Oy =
i
psi
Txy =
i
psi

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