A 1.000 mL aliquot of a solution containing Cu²+ and Ni2+ is treated with 25.00 mL of a 0.03835 M EDTA solution. The solution is then back titrated with 0.02240 M Zn²+ solution at a pH of 5. A volume of 15.56 mL of the Zn2+ solution was needed to reach the xylenol orange end point. A 2.000 mL aliquot of the Cu²+ and Ni²+ solution is fed through an ion- exchange column that retains Ni²+. The Cu²+ that passed through the column is treated with 25.00 mL of 0.03835 M EDTA. This solution required 19.69 mL of 0.02240 M Zn²+ for back titration. The Ni²+ extracted from the column was treated witn 25.00 mL of 0.03835 M EDTA. How many milliliters of 0.02240 M Zn²+ is required for the back titration of the Ni²+ solution? volume: mL

A 1.000 mL aliquot of a solution containing Cu²+ and Ni2+ is treated with 25.00 mL of a 0.03835 M EDTA solution. The solution is then back titrated with 0.02240 M Zn²+ solution at a pH of 5. A volume of 15.56 mL of the Zn2+ solution was needed to reach the xylenol orange end point. A 2.000 mL aliquot of the Cu²+ and Ni²+ solution is fed through an ion- exchange column that retains Ni²+. The Cu²+ that passed through the column is treated with 25.00 mL of 0.03835 M EDTA. This solution required 19.69 mL of 0.02240 M Zn²+ for back titration. The Ni²+ extracted from the column was treated witn 25.00 mL of 0.03835 M EDTA. How many milliliters of 0.02240 M Zn²+ is required for the back titration of the Ni²+ solution? volume: mL

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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