A 0.800-cm-tall candle flame is 1.90 m from a wall. You happen to have a lens with a focal length of 22.0 cm, and notice while playing around with it that there are two locations you can place the lens and form a well-focused image of the candle flame on the wall. With the lens in the location furthest from the wall, what is the height of the image? (Input a positive height):
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- In order to heighten your enjoyment of your 29 carat blue diamond, you view it through a lens held close to your right eye at an angular magnification of 5.1. The distance of your right eye's near point is 25 cm. What is the focal length f of the lens in centimeters? f = ?cmTwo lenses are mounted d = 39 cm apart on an optical bench. The focal length of the first lens is f1 = 9.8 cm and that of the second lens is f2 = 3.1 cm. An object of height ho = 4.9 cm is placed at a distance of do = 24 cm in front of the first lens. Now consider the two-lens system and the final image it forms, i.e., the image created by the second lens. What is the distance, in centimeters, between the object and its final image? D =?A lens of focal length +24.0 cm is at x 0, and a second lens of focal length -24.0 cm is located at x = 16.0 cm. Let the positive x-direction be to the right. At what position x is the final image of an object that is 48.0 cm to the left of the positive lens? cm X = What is the magnification m of the image?.(Remember that magnification can be positive or negative.) m = The image is and virtual real Where should your eye be located and directed to see the image? O looking left from the right of both lenses looking left from between the lenses looking right from between the lenses O looking right from the left of both lenses Question Source: Freedman College Physic
- You use a camera with a lens of focal length 50.0 mm to take a picture of a 2.50 m tall statue located 7.20 m away. If the image height on the film is 18.2 mm, what is the distance from the lens to the film?= A doublet lens consists of two lenses in effective contact. The front lens is biconvex with fi +37.5 cm, and the second is biconcave with f2 = -150 cm. An object of height 2 cm is placed at 80 cm to the left of the combined lens. Calculate the position of the image, and the image height.Two converging lenses, each of focal length 14.9 cm, are placed 39.6 cm apart, and an object is placed 30.0 cm in front of the first lens. Where is the final image formed? The image is located cm ---Location--- in front of the first lens. in front of the second lens. behind the second lens. What is the magnification of the system? M = ✕
- A convex lens made of glass (n = 1.50) has a focal distance of 20 cm. An identical looking piece of plastic with same shape and thickness has a focal distance of 25 cm. Which of the following could be the index of refraction of the plastic? O 1.0 O 1.4 O 1.6 O 1.5It is your first day at work as a summer intern at an optics company. Your supervisor hands you a diverging lens and asks you to measure its focal length. You know that with a converging lens, you can measure the focal length by placing an object a distance ss to the left of the lens, far enough from the lens for the image to be real, and viewing the image on a screen that is to the right of the lens. By adjusting the position of the screen until the image is in sharp focus, you can determine the image distance s′s′ and then use the equation 1s+1s′=1f1s+1s′=1f, to calculate the focal length ff of the lens. But this procedure won't work with a diverging lens−−by itself, a diverging lens produces only virtual images, which can't be projected onto a screen. Therefore, to determine the focal length of a diverging lens, you do the following: First you take a converging lens and measure that, for an object 20.0 cmcm to the left of the lens, the image is 29.7 cmcm to the right of the lens.…An object is placed 27 cm in front of a diverging lens having a focal length of magnitude 50 cm. What is the image distance, in cm? Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement.
- A 4.0-cm tall object is placed 50.0 cm from a diverging lens having a focal length of magnitude 25.0 cm. What are the nature and location of the image? The image is O virtual, 1.3 cm tall, and 7 cm from the lens on the same side of the object. O real, 4.0 cm tall, and 20 cm from the lens on the side opposite the object. O virtual, 4.0 cm tall, and 20 cm from the lens on the side opposite the object. O virtual, 2.0 cm tall, and 10 cm from the lens on the side opposite the object. real, 1.3 cm tall, and 7 cm from the lens on the same side of the object.A 4 cm tall light bulb is placed a distance of 35.5 cm from a diverging lens whose focal length magnitude is 12.2 cm. Determine the image distance from the lens, the image height, and the magnification. Put into words what your calculations physically represent about the image.I continue to get the wrong answer. TIA.