A 0.6006-g sample of Ni/Cu condenser tubing was dissolved in acid and diluted to 100 mL in a volumetric flask. Titration of both ions in a 25.0ml aliquot of this solution required 45.81 mL of 0.052285M EDTA. Mercaptoacetic acid and NH3 were then introduced; production of the Cu complex with the former resulted in the release of an equivalent amount of EDTA, which required 22.85ml titration with 0.07238M Mg2+. Calculate the %Ni (59.693 g/mol) in the alloy.
A 0.6006-g sample of Ni/Cu condenser tubing was dissolved in acid and diluted to 100 mL in a volumetric flask. Titration of both ions in a 25.0ml aliquot of this solution required 45.81 mL of 0.052285M EDTA. Mercaptoacetic acid and NH3 were then introduced; production of the Cu complex with the former resulted in the release of an equivalent amount of EDTA, which required 22.85ml titration with 0.07238M Mg2+. Calculate the %Ni (59.693 g/mol) in the alloy.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A 0.6006-g sample of Ni/Cu condenser tubing was dissolved in acid and diluted to 100 mL in a volumetric flask. Titration of both ions in a 25.0ml aliquot of this solution required 45.81 mL of 0.052285M EDTA. Mercaptoacetic acid and NH3 were then introduced; production of the Cu complex with the former resulted in the release of an equivalent amount of EDTA, which required 22.85ml titration with 0.07238M Mg2+. Calculate the %Ni (59.693 g/mol) in the alloy.
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