Fill in table one and two please!! 93157*= shouldbe equal11. If the impulse momentum theorem is correct, the change in the momentum will be equal to theimpulse for each trial. Experimental measurements error along with friction and shifting of thetrack or force sensors will keep the two from being the same. One way to compare the two is tofind their percent different. Do this for the change in momentumAp=mv-mv₁Oand the impulse calculation12. Fill in Table #112TrialI = FAt*Table 1:Impulse[FFdt = FAtInitial momentum(N·s)Final momentum(N·s)(N·s)*Change inmomentum Ap(N·s)Velocity trial 1: -1.060 m/s (initial)Part 2:(velocity).-0.033mls (final):Trial 2 - 1.023mls (in)Repeat the experiment using a double rubber band. :-0.009mis (final)TrialImpulse[ Fdt = FAt(N·s)LTable 2:Initial momentum Final momentum(N·s)(N·s)Part 3:AVelocity 2: -1.014 m/s (i): -0.085 mis (f)0.860ml sci: 0.031 mis(f)Change inmomentum Ap(N·s)tralMoni

Answered: Image /qna-images/answer/ad4201a0-9fff-469f-9c15-8fa53b785042.jpg

Answered: 93157 *= should be equal 11. If the…

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter8: Momentum And Collisions

Section: Chapter Questions

Problem 38P

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A ball of mass 0.470 kgkg moving east (+x+xdirection) with a speed of 3.84 m/sm/s collides head-on with a 0.235 kgkg ball at rest. Assume that the collision is perfectly elastic. 1.What is be the speed of the 0.470-kgkg ball after the collision? Express your answer to three significant figures and include the appropriate units. 2. What is be the direction of the velocity of the 0.470-kgkg ball after the collision? East or west? 3.What is the speed of the 0.235-kgkg ball after the collision? Express your answer to three significant figures and include the appropriate units. 4.What is the direction of the velocity of 0.235-kgkg ball after the collision? East or west?
Which is the formula that describes the magnitude of impulse on an object? A. impulse = mass x acceleration B. impulse = mass x change in velocity C. impulse = mass * (velocity)2 x 0.5 D. impulse = mass x velocity
Learning Goal: To understand the relationship between force, impulse, and momentum. The effect of a net force EF acting on an object is related both to the force and to the total time the force acts on the object. The physical quantity impulse J is a measure of both these effects. For a constant net force, the impulse is given by J = FAt. The impulse is a vector pointing in the same direction as the force vector. The units of J are N. sor kg · m/s. Recall that when a net force acts on an object, the object will accelerate, causing a change in its velocity. Hence the chiect's momentum in- mail will also change. The Figure F (N) L 12,000 0.0007 1 of 1 t (s) In Parts A, B, C consider the following situation. In a baseball game the batter swings and gets a good solid hit. His swing applies a force of 12,000 N to the ball for a time of 0.70 × 10-³ s. Part A Assuming that this force is constant, what is the magnitude J of the impulse on the ball? Enter your answer numerically in newton…
A 5.0 kg mass moving with a velocity of 8.0 m/s East has an impulse applied to it which causes its velocity to change to 20.0 m/s East. a. Find the impulse of the mass. b. Find the force if the impulse was applied for 3.0s.
1. What are the equations for linear momentump and kinetic energy K? Please define the variables. 2. Please define concisely and in your own words the concept of conservation. Describe conservation of momentum and kinetic energy. 3. Briefly describe the difference between elastic and inelastic collisions and give an example of each. Describe these collisions in terms of the kinetic energy and momentum. 4. A moving object collides with and sticks to a stationary object. Do the combined objects move slower, faster or at the same speed as the original moving object? 5. What is the expected value of the ratio of the final and initial momenta, pf/p; ?
p = mv J = Ft Ft = m Av Calculate the change in momentum of a 0.5 kg ball that strikes the floor at 15 m/s and bounces back up at 12 m/s. N
Please show steps and equations used for each problem
What are the units for momentum. what are the units for impulse
what equations will we use?
2. A 400.0 g cart moving at 0.360 m/s has how much momentum? (careful...units!) 3. If the cart in question 2 was to bounce back and return with a velocity of -0.240 m/s , what is its change in momentum (remember that momentum is a vector quantity)? This change in momentum is called the impulse.
1. What is the Law of “Conservation of Linear Momentum” and its formula? What is the condition of “Conservation of Kinetic Energy in Collision”? 2. Objects M and m with velocities V and v collide each other elastically. If their velocities after collision are V’ and v’ write the equation of linear momentum of the system before and after the collision and drive V’ from it. 3. Write Theoretical and Experimental formulas of “Fractional Energy Loss”.
i. Draw the balls and the approximate momentum vectors before and after the collision. ii. What is the final velocity of the second ball, v'2? iii. Is the collision elastic? What is the energy loss in the collision?

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