Now suppose we remove the source of emf and begin with the charge on the capacitor equal to QO. When we close the switch the capacitor discharges. (The energy stored in the capacitor's electric field is dissipated in the resistor.) Applying Kirchoff's loop rule for clockwise travel starting at the switch gives us R C W Solving the loop equation using calculus yields for the charge and current respectively - RC i= བགས པ#ད] RC Suppose your RC series circuit has a 2.0-ohm resistor ad a 2.0 X10-бF capacitor. The initial charge, QO on the capacitor is 2.0 X10-6 C. The time constant is 4.0x 10-6 s. Calculate the q and i at 4.0X10-6s 0.74 x 10-6 and 0.19 A 0.72 x10-6 C and 0.72 A 2.0 x 10-6 C, 0.74 A 0.74 C and 2.0 x10-6 A

University Physics Volume 2
18th Edition
ISBN:9781938168161
Author:OpenStax
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Chapter13: Electromagnetic Induction
Section: Chapter Questions
Problem 61P: A 120-V, series-wound motor has a field resistance of 80 and an armature resistance of 10. When it...
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Now suppose we remove the source of emf and begin with the charge on the capacitor equal to QO. When we close the switch the capacitor discharges. (The
energy stored in the capacitor's electric field is dissipated in the resistor.) Applying Kirchoff's loop rule for clockwise travel starting at the switch gives us
R
C
W
Solving the loop equation using calculus yields for the charge and current respectively
-
RC
i=
བགས པ#ད]
RC
Suppose your RC series circuit has a 2.0-ohm resistor ad a 2.0 X10-бF capacitor. The initial charge, QO on the capacitor is 2.0 X10-6 C. The time constant is
4.0x 10-6 s. Calculate the q and i at 4.0X10-6s
0.74 x 10-6 and 0.19 A
0.72 x10-6 C and 0.72 A
2.0 x 10-6 C, 0.74 A
0.74 C and 2.0 x10-6 A
Transcribed Image Text:Now suppose we remove the source of emf and begin with the charge on the capacitor equal to QO. When we close the switch the capacitor discharges. (The energy stored in the capacitor's electric field is dissipated in the resistor.) Applying Kirchoff's loop rule for clockwise travel starting at the switch gives us R C W Solving the loop equation using calculus yields for the charge and current respectively - RC i= བགས པ#ད] RC Suppose your RC series circuit has a 2.0-ohm resistor ad a 2.0 X10-бF capacitor. The initial charge, QO on the capacitor is 2.0 X10-6 C. The time constant is 4.0x 10-6 s. Calculate the q and i at 4.0X10-6s 0.74 x 10-6 and 0.19 A 0.72 x10-6 C and 0.72 A 2.0 x 10-6 C, 0.74 A 0.74 C and 2.0 x10-6 A
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