6. 3.2 Block on Block = = 11.0 kg as shown in the figure below. .32, and the surface on which the more 2a A block of mass m = 3.0 kg is at rest on a larger block of mass M The coefficient of kinetic friction between the two blocks is μk massive block rests is frictionless. A horizontal force of Fp = 12.2 N acts on the smaller block, setting it into motion. The right edge of the smaller block is d = 2.5 m from the right edge of the small block. Fp m Мк M How long will it take the smaller block to make it to the right side of the larger block? Please give your answer in S. 8.45 Correct The net force on the smaller box is the applied force minus the frictional force. The distance the smaller box has to go is 2.5 plus the distance the larger box moves. The acceleration of the larger box can be calcultated because the only force acting on it is the frictional force. Using kinematic equations and F =ma you can then solve for t. 7. 2b How far will the larger block move in this time? Please give your answer in m. No answer (X) Incorrect The answer you gave is not a number. 7a You are on a fishing trip, not catching anything, and bored - time for physics! You drop your 50 g weight to the bottom of the lake under constant tension from the string of magnitude 0.1 N. The damping constant for your falling weight is 2.5 kg/s. What is the terminal velocity of the weight? Give your answer in m/s and assume the positive direction is upwards. 0.6397 (X) Incorrect 2. 7b If it takes 500 s for the weight to reach the bottom of the lake, how deep is the lake? Give your answer in m. 319.85 Incorrect 3. 3.8 Agent Smith 8a Agent Smith, who has a mass of 70 kg, is trapped in the back of a closed truck going down the road at 35 m/s . The driver applies the breaks and slows down to 20 m/s in 1.8 s. What ficticious force does Agent Smith feel? Please give your answer in N. Magnitude only. 1361 (X Incorrect

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
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6. 3.2 Block on Block
=
=
11.0 kg as shown in the figure below.
.32, and the surface on which the more
2a A block of mass m = 3.0 kg is at rest on a larger block of mass M
The coefficient of kinetic friction between the two blocks is μk
massive block rests is frictionless. A horizontal force of Fp = 12.2 N acts on the smaller block, setting it into
motion. The right edge of the smaller block is d = 2.5 m from the right edge of the small block.
Fp
m
Мк
M
How long will it take the smaller block to make it to the right side of the larger block? Please give your answer in S.
8.45
Correct
The net force on the smaller box is the applied force minus the frictional force. The distance the smaller
box has to go is 2.5 plus the distance the larger box moves. The acceleration of the larger box can be
calcultated because the only force acting on it is the frictional force. Using kinematic equations and
F =ma you can then solve for t.
7. 2b How far will the larger block move in this time? Please give your answer in m.
No answer
(X) Incorrect
The answer you gave is not a number.
Transcribed Image Text:6. 3.2 Block on Block = = 11.0 kg as shown in the figure below. .32, and the surface on which the more 2a A block of mass m = 3.0 kg is at rest on a larger block of mass M The coefficient of kinetic friction between the two blocks is μk massive block rests is frictionless. A horizontal force of Fp = 12.2 N acts on the smaller block, setting it into motion. The right edge of the smaller block is d = 2.5 m from the right edge of the small block. Fp m Мк M How long will it take the smaller block to make it to the right side of the larger block? Please give your answer in S. 8.45 Correct The net force on the smaller box is the applied force minus the frictional force. The distance the smaller box has to go is 2.5 plus the distance the larger box moves. The acceleration of the larger box can be calcultated because the only force acting on it is the frictional force. Using kinematic equations and F =ma you can then solve for t. 7. 2b How far will the larger block move in this time? Please give your answer in m. No answer (X) Incorrect The answer you gave is not a number.
7a You are on a fishing trip, not catching anything, and bored - time for physics! You drop your 50 g weight to the
bottom of the lake under constant tension from the string of magnitude 0.1 N. The damping constant for your
falling weight is 2.5 kg/s.
What is the terminal velocity of the weight? Give your answer in m/s and assume the positive direction is
upwards.
0.6397
(X) Incorrect
2. 7b If it takes 500 s for the weight to reach the bottom of the lake, how deep is the lake? Give your answer in m.
319.85
Incorrect
3. 3.8 Agent Smith
8a Agent Smith, who has a mass of 70 kg, is trapped in the back of a closed truck going down the road at 35 m/s
. The driver applies the breaks and slows down to 20 m/s in 1.8 s.
What ficticious force does Agent Smith feel? Please give your answer in N. Magnitude only.
1361
(X Incorrect
Transcribed Image Text:7a You are on a fishing trip, not catching anything, and bored - time for physics! You drop your 50 g weight to the bottom of the lake under constant tension from the string of magnitude 0.1 N. The damping constant for your falling weight is 2.5 kg/s. What is the terminal velocity of the weight? Give your answer in m/s and assume the positive direction is upwards. 0.6397 (X) Incorrect 2. 7b If it takes 500 s for the weight to reach the bottom of the lake, how deep is the lake? Give your answer in m. 319.85 Incorrect 3. 3.8 Agent Smith 8a Agent Smith, who has a mass of 70 kg, is trapped in the back of a closed truck going down the road at 35 m/s . The driver applies the breaks and slows down to 20 m/s in 1.8 s. What ficticious force does Agent Smith feel? Please give your answer in N. Magnitude only. 1361 (X Incorrect
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