9) A public opinion poll surveyed a simple randomsample of 1000 voters. Respondents were classified bygender (male or female) and by voting preference(Republican, Democrat, or Independent). Results areshown in the contingency table below.Voting PreferencesRow totalMaleFemaleColumn totalRepublican Democrat Independent20015050250450300450501004006001000Is there a gender gap? Do the men's voting preferencesdiffer significantly from the women's preferences? Use a0.05 level of significance.

Answered: 9) A public opinion poll surveyed a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The Women’s Institutional Studies group at a Midwestern university wanted to compare the percentages of female faculty members in the various units on campus in Spring 2004. Of particular interest were the percentages of female faculty in the College of Education and in the College of Business . In a sample of 80 College of Education faculties, there were 36 females, and in a sample of 70 College of Business faculties, there were 15 females. Based upon this sample information, which of the following is the 98% confidence interval for the difference in the actual percentages of female faculty between College of Education and College of Business ? a. (0.075, 0.405). b. (0.123, 0.357). c. (-0.012, 0.252). d. (0.058, 0.422). e. (0.101, 0.379).
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I AM RESUBMITTING THIS QUESTION FOR DIFFERENT PARTS. I NEED THE LAST 3 MULTIPLE CHOICE QUESTIONS ANSWERED. 5, 6, AND 7 Before the furniture store began its ad campaign, it averaged 160 customers per day. The manager is investigating if the average has changed since the ad came out. The data for the 16 randomly selected days since the ad campaign began is shown below: 131, 127, 148, 143, 141, 153, 158, 145, 138, 163, 164, 148, 166, 154, 170, 133 Assuming that the distribution is normal, what can be concluded at the αα = 0.05 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer < = ≠ > H1:H1: ? p μ Select an answer = > ≠ < The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? ≤ > αα Based…
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