#1According to research, foot length of women is normally distributed with mean 9.58 inchesand standard deviation 0.51 inch. The distríbution is useful to shoe manufacturers, shoestores, and related merchants because it permits them to make informed decisions about sheproduction, inventory and so forth.a) Sketch a Normal curve and place on it the values that correspond to 21, 12, ±3 standarddeviations of the mean, as well as the mean itself.Women's Size Conversionsb) What percentage of women have foot lengths between9.5 and 10 inches? Show all your computations andshade the area under the Normal curve. Explain howUS Sizes Euro Sizes UK Sizes inchesCM2.1875" 20.83524.5352.52.375"21.3you obtainedyour answer.8.5335-3621.65.5363.5a.7522.2636-378.375"22.546.5459.0625" 2337737-3859.25"23.57.5385.59.375"23.8c) What percentage of women have foot lengths below 9inches? Show all your computations and shade the area 8.5under the Normal curve. Explain how89.538-39624.1396.59.6875" 24.6obtained939-4079.875" 25.1you9.5407.510254your answer.1040-41810.1875" 25.910.5418.510.3125" 26.210.51141-42926.711.5429.510.6875" 27.142-4310.875 27.61210

Given mean = 9.58 inchesstandard deviation = 0.51 inchThe values one, two, three standard deviations…

Answered: #1 According to research, foot length…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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During a quality assurance check, the actual contents (in grams) of six containers of protein powder were recorded as 1524, 1526, 1499, 1512, 1532, and 1514. (a) Find the mean and the median of the contents. (b) The third value was incorrectly measured and is actually 1518. Find the mean and the median of the contents again. (c) Which measure of central tendency, the mean or the median, was affected more by the data entry error? (a) The mean is 1517.8. (Round to one decimal place as needed.) The median is 1519 (Type an integer or a decimal. Do not round.) (b) The mean is 1521 (Round to one decimal place as needed.) The median is 1521 (Type an integer or a decimal. Do not round.) (c) After correcting the error, the mean affected more. (Round to one decimal place as needed.) by and the median by The was

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