8.00 mL of 4.00 x 10-3 M Fe(NO3)3 (4.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 7.00 mL of 8.00 x 10-3 M KSCN (8.00 times 10 to the minus 3rd power M KSCN) along with 5.00 mL of water. The concentration of [F e(SCN)2+] was found to be 1.00 x 10-4 M (1.00 times 10 to the minus 4th power M) at equilibrium. How many moles of SCN- (SCN minus) are present in the solution at equilibrium? Express your answer as a decimal number (no exponents).
8.00 mL of 4.00 x 10-3 M Fe(NO3)3 (4.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 7.00 mL of 8.00 x 10-3 M KSCN (8.00 times 10 to the minus 3rd power M KSCN) along with 5.00 mL of water. The concentration of [F e(SCN)2+] was found to be 1.00 x 10-4 M (1.00 times 10 to the minus 4th power M) at equilibrium. How many moles of SCN- (SCN minus) are present in the solution at equilibrium? Express your answer as a decimal number (no exponents).
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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8.00 mL of 4.00 x 10-3 M Fe(NO3)3 (4.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 7.00 mL of 8.00 x 10-3 M KSCN (8.00 times 10 to the minus 3rd power M KSCN) along with 5.00 mL of water. The concentration of [F e(SCN)2+] was found to be 1.00 x 10-4 M (1.00 times 10 to the minus 4th power M) at equilibrium. How many moles of SCN- (SCN minus) are present in the solution at equilibrium? Express your answer as a decimal number (no exponents).
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