8.00 mL of 4.00 x 10-3 M Fe(NO3)3 (4.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 4.00 mL of 8.00 x 10-3 M KSCN (8.00 times 10 to the minus 3rd power M KSCN) along with 4.00 mL of water. The concentration of [F e(SCN)2+] was found to be 2.00 x 10-4 M (2.00 times 10 to the minus 4th power M) at equilibrium.How many moles of F e3+ are present in the solution at equilibrium? Express your answer as a decimal number (no exponents).

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Answered: 8.00 mL of 4.00 x 10-3 M Fe(NO3)3 (4.00…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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8.00 mL of 4.00 x 10^-3 M Fe(NO₃)₃ (4.00 times 10 to the minus 3rd power M F e (NO3)3) is added to 4.00 mL of 8.00 x 10^-3 M KSCN (8.00 times 10 to the minus 3rd power M KSCN) along with 4.00 mL of water. The concentration of [F e(SCN)²⁺] was found to be 2.00 x 10^-4 M (2.00 times 10 to the minus 4th power M) at equilibrium.How many moles of F e³⁺ are present in the solution at equilibrium? Express your answer as a decimal number (no exponents).

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