8. A large online retailer is analyzing how frequently their product WonderWidget" is returned. Out of 345 WonderWidgets bought, 48 were returned. (a) Find the 97% confidence interval for the long-run proportion of Wonder Widgets returned. (b) If the retailer wanted to obtain a 97% confidence interval with a margin of error ±0.03, how many purchases it should analyze?
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- The ability to find a job after graduation is very important to GSU students as it is to the students at most colleges and universities. Suppose we take a poll (random sample) of 3878 students classified as Juniors and find that 3241 of them believe that they will find a job immediately after graduation. Find the 95% confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation. Use Z = 1.96. Use the unrounded values in Excel to find the answers to #2, #3 and #4. 1. Find the sample proportion of GSU Juniors who believe that they will, immediately, be graduation. 2. The standard error for sample proportion has a value of 3. The margin of error has a value of --5. At Community Hospital, the burn center is experimenting with a new plasma compress treatment. A random sample of 316 patients with minor burns received the plasma compress treatment. Of these patients, 259 had no visible scars after treatment. Another random sample of 419 patients with minor burns received no plasma compress treatment. For this group, 94 had no visible scars after treatment. Find a 90% confidence interval for the difference between the two population proportions.A scientist claims that 65% of U.S. adults believe humans contribute to an increase in global temperature. A 95% confidence interval for the proportion of U.S. adults who say that the activities of humans are contributing to an increase in global temperatures is found to be (0.626, 0.674). Does this confidence interval support the scientist's claim? Since 0.65 falls in the confidence interval, the scientist’s claim is incorrect. Since 0.65 does not fall in the confidence interval, the scientist’s claim is incorrect. Since 0.65 does not fall in the confidence interval, the scientist’s claim is correct. Since 0.65 falls in the confidence interval, the scientist’s claim is correct.
- Joe’s Pizza Joint found that 64.2% of the 328 pizzas sold last week included pepperoni. Find a98% confidence interval for the proportion of Joe’s customers that order pepperoni.A scientist wondered if there was a difference in the average daily intake of dairy products between men and women. He took a sample of n1 = 50 adult men and n2 = 50 adult women and recorded their daily intakes of dairy products in grams per day. A summary of the sample results of it is presented in the table. He constructs a 95% confidence interval for the difference in the average daily intakes of dairy products for men and women. Can it be concluded that there is a difference in the average daily intakes for men and women?In a random sample of 250 high school students, it was found that 85.2% (213) of them later graduated. The 95% confidence interval is (-0.065,0.065) and the 98% confidence interval is (-0.077,0.077) for the true proportion of all high school students who graduate. Compare the two proportions.
- The heart rate variability (HRV) of police officers was the subject of research published in a biology journal. HRV is defined as the variation in the time intervals between heartbeats. A measure of HRV was obtained for each in a sample of 331 police officers from the same city. (The lower the measure of HRV, the more susceptible the officer is to cardiovascular disease.) For the 76 officers diagnosed with hypertension, a 90% confidence interval for the mean HRV was (7.2,121.3). For the 255 officers that are not hypertensive, a 90% confidence interval for the mean HRV was (141.6,189.9). Use this information to complete parts a through d below. a. What confidence coefficient was used to generate the confidence intervals? (Type an integer or a decimal. Do not round) b. Give a practical interpretation of both of the 90% confidence intervals. Use the phrase '90% confident" in your answer. The researchers can be 90% confident that the Type integers or decimals. Do not round.) V mean HRV for…2. A study investigated 62 students who were randomly assigned into two equal size groups. Group A could listen to music as they studied for a big test, while group B was not allowed to listen to music. After the exam, they calculated a 95% confidence interval for the mean difference in scores between groups, which was (-1.2, 3.4). Explain what one can conclude from this confidence interval. Does it appear that is better to study while listening to music?A new drug to treat high cholesterol is being tested by pharmaceutical company. The cholesterol levels for 8 patients were recorded before administering the drug and after. The mean difference in total cholesterol levels (after - before) was 15.91 mg/dL with a standard deviation of 15.2714 mg/dL. Create a 95% confidence interval for the true average difference in cholesterol levels by the drug. Question 9 options: 1) (-3.1428, 28.6772) 2) (3.1428, 28.6772) 3) (3.4593, 28.3607) 4) (10.5107, 21.3093) 5) (13.5454, 18.2746)
- A poll reported that only 645 out of a total of 2029 adults in a particular region said they had a "great deal of confidence" or "quite a lot of confidence" in the public school system. This was down 5 percentage points from the previous year. Assume the conditions for using the CLT are met. Find a 95% confidence interval for the proportion that express a great deal of confidence or quite a lot of confidence in the public schools, and interpret this interval. The 95% confidence interval for the proportion that express a great deal of confidence or quite a lot of confidence in the public schools is ____A poll reported that only 507 out of a total of 1809 adults in a particular region said they had a "great deal of confidence" or "quite a lot of confidence" in the public school system. This was down 5 percentage points from the previous year. Assume the conditions for using the CLT are met. Find a 95% confidence interval for the proportion that express a great deal of confidence or quite a lot of confidence in the public schools, and interpret this interval.A quality control inspector selects 12 bottles of apple juice at random from a single day’s production. The mean amount of apple juice in the bottles is 298.3 milliliters, and the 95% confidence interval for the true mean amount of juice dispensed per bottle is (296.4, 300.2). Does this interval give the quality control inspector reason to believe that the mean amount of juice in today’s bottles differs from 300 milliliters, as the juice label promises? Yes, since the sample mean of 298.3 ml is less than 300 ml. Yes, since nearly the entire confidence interval is less than the advertised value of 300 ml. No, since the sample mean of 298.3 ml is in the confidence interval. No, since the advertised value of 300 ml is in the confidence interval.