What is the margin of error for the population mean at 90% confidence level for the following information: 5.110.86.24.35.77.34.77.58.75.58.77.76.56.211.48.15.512.36.47.27.69.28.96.94.89.411.75.67.113.4
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What is the margin of error for the population
10.8
6.2
4.3
5.7
7.3
4.7
7.5
8.7
5.5
8.7
7.7
6.5
6.2
11.4
8.1
5.5
12.3
6.4
7.2
7.6
9.2
8.9
6.9
4.8
9.4
11.7
5.6
7.1
13.4
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- The daily salaries of security guards for 10 security agencies are as follows: P350, P400, P375, P420, P500, P470, P380, P450, P520, and P460. What is the point estimate for the mean? Find the 95% confidence interval of the mean for the salaries of security guards in the area.A 95% confidence interval for mean was found to be (18.54, 21.22). What was the margin of error? O A. 1.34 O B. 2.68 O C.4.97 O D. 19.88 O E. 9.94Explain how to find the 95% confidence interval for the mean by hand using the following data set 57,60,61,55,60,64,55,53,63,57,51,63,66,62,53,60,52,61,66,62
- Construct a 90% confidence intervalA second-semester junior at a large high school wants to estimate the number of colleges a senior applies to on average before deciding where they will attend. The junior randomly selects 19 seniors and asks them how many colleges they applied to and records the number. Use the data below to construct a 99% confidence interval to estimate the true mean number of colleges seniors at this school apply to before deciding about which college to attend. 1, 1, 2, 2, 2, 3, 3, 3, 4, 4, 4, 5, 5, 5, 6, 7, 7, 8, 9 4. Conclude. In repeated sampling, 99% of the time, the sample number of colleges seniors applied to will be 4.26. In repeated sampling, 99% of the time, the true mean number of colleges seniors apply to will be captured in the constructed interval. 99% of seniors will apply to 4.26 colleges. We are 99% confident that the constructed interval captures the true number of colleges seniors applied to.A second-semester junior at a large high school wants to estimate the number of colleges a senior applies to on average before deciding where they will attend. The junior randomly selects 19 seniors and asks them how many colleges they applied to and records the number. Use the data below to construct a 99% confidence interval to estimate the true mean number of colleges seniors at this school apply to before deciding about which college to attend. 1, 1, 2, 2, 2, 3, 3, 3, 4, 4, 4, 5, 5, 5, 6, 7, 7, 8, 9 3. Do. Use technology to find the mean and standard deviation of the sample. Round each answer to 2 decimal places. Use those values and t* from the table to calculate the confidence interval. Round the endpoints to 1 decimal place. 99% confidence interval is (, )
- 1. The owner of Britten's Egg Farm wants to estimate the mean number of eggs laid per chicken. A sample of 20 chickens shows they laid an average of 20 eggs per month with a standard deviation of 2 eggs per month.A department chair wanted to know whose students performed better on a common pass/fail final exam: Smith's or Jones's. Of Smith's 57 students, 49 passed. Of Jones's 75 students, 51 passed. Construct a 95% confidence interval for the difference between the two proportions. Be sure to interpret this interval in a complete sentence.Suppose you needed to form a 92% confidence interval for a population mean. What z value would you use?
