3. (Graduation) The following table reports the number at risk and exits by the event for age under 30. Age(x) lx 0 dx Age(x) Ix dx 103 0 15 64 4 1 -234567822=22: 103 0 16 60 4 103 3 17 56 7 100 1 18 49 10 99 1 19 39 6 98 3 20 33 3 95 2 21 30 10 10 11 12 13 14 22222222 93 1 22 20 8 92 2 23 124 90 86 82 79 75 72 1443 +38 4 29 222222 24 8 3 25 5 26 5 27 2 2 1 Table 2: Actuarial table. Under Binomial model, use the following inverse logit model for graduation qx = logit¯¹ (pn(x)), where p(x) = 0 + α₁x + a2x² + ... + Anx”. Compare the results for n = 1, n = 2 and n = 3. Provide statistical tests (x²-test, standardized deviations test, sign test, change-of-sign test, and lag-1 serial correlation test) on the quality of goodness-of-fit of the model.
3. (Graduation) The following table reports the number at risk and exits by the event for age under 30. Age(x) lx 0 dx Age(x) Ix dx 103 0 15 64 4 1 -234567822=22: 103 0 16 60 4 103 3 17 56 7 100 1 18 49 10 99 1 19 39 6 98 3 20 33 3 95 2 21 30 10 10 11 12 13 14 22222222 93 1 22 20 8 92 2 23 124 90 86 82 79 75 72 1443 +38 4 29 222222 24 8 3 25 5 26 5 27 2 2 1 Table 2: Actuarial table. Under Binomial model, use the following inverse logit model for graduation qx = logit¯¹ (pn(x)), where p(x) = 0 + α₁x + a2x² + ... + Anx”. Compare the results for n = 1, n = 2 and n = 3. Provide statistical tests (x²-test, standardized deviations test, sign test, change-of-sign test, and lag-1 serial correlation test) on the quality of goodness-of-fit of the model.
Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015
1st Edition
ISBN:9781680331141
Author:HOUGHTON MIFFLIN HARCOURT
Publisher:HOUGHTON MIFFLIN HARCOURT
Chapter9: Solving Quadratic Functions
Section: Chapter Questions
Problem 4CA
Related questions
Question
Please assist with the following questions with the answers.
Transcribed Image Text:3. (Graduation)
The following table reports the number at risk and exits by the event for age under 30.
Age(x) lx
0
dx
Age(x) Ix dx
103
0
15
64 4
1
-234567822=22:
103 0
16
60 4
103 3
17
56 7
100 1
18
49 10
99
1
19
39
6
98
3
20
33 3
95 2 21
30 10
10
11
12
13
14
22222222
93 1 22
20
8
92
2
23
124
90
86
82
79
75
72
1443 +38
4
29
222222
24
8
3
25
5
26
5
27
2
2
1
Table 2: Actuarial table.
Under Binomial model, use the following inverse logit model for graduation
qx = logit¯¹ (pn(x)), where p(x) = 0 + α₁x + a2x² + ... + Anx”.
Compare the results for n = 1, n = 2 and n = 3.
Provide statistical tests (x²-test, standardized deviations test, sign test, change-of-sign
test, and lag-1 serial correlation test) on the quality of goodness-of-fit of the model.
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