Assume the values in your dataset are a sample from a larger population, even if that doesn't make sense for your application. Form a 95% confidence interval for the population proportion for this variable. Interpret your confidence interval for a business audience from the following results Count of Gender Row Labels Female Male Grand Total 56.67% 43.33% margin of error 1.46 100.00% sample porpotion 0.57 upper bound 2.03 lower bound -0.89
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- Find a credible journal article or website where confidence intervals were used to make informed decisions regarding a real world applicationa critic points out that this 95 % confidence interval is only accurate if the statistic follows a normal distrubution , or if the normal model is a good approximation. is this true for this data? explainWe wish to estimate what percent of adult residents in Ventura County like chocolate. Out of 500 adult residents sampled, 367 like chocolate. Based on this, construct a 90% confidence interval for the proportion (p) of adult residents who like chocolate in Ventura County.
- If the margin of error in an estimate for the mean weight of a shipment is + or -2 pounds at a confidence level of 95 percent, what will be the margin of error at a confidence level of 98 percent? Be sure to show how you arrived at your answer.Suppose a different police department says their SRS resulted in a 95% confidence interval of 10.1% to 15.1%. What is their point estimator and margin of error?During the recovery from the great Recession of 2007-2009, the economic situation for many families improved. However, in 2011 the recovery was slow and it was uncertain as how much had really changed on the national level. To estimate the national average of the percent of low income working families from each of the country's reporting jurisdictions could be used to calculate a point estimate and create a related confidence interval. With this confidence interval a better picture of the nation's recovery can be had legislative decisions can be made. 1. Describe in two or three sentences how a simple random sample of size n =20 could be obtained from the full list of jurisdictions provided for use with this assignment. 2. A researcher reported that a sample of size n =30 produced a sample mean of 32.56% and sample standard deviation of 6.56%. Use this information to calculate a 90% confidence interval for the national average for the "percent of low income working families". Provide…
- A poll reported that only 507 out of a total of 1809 adults in a particular region said they had a "great deal of confidence" or "quite a lot of confidence" in the public school system. This was down 5 percentage points from the previous year. Assume the conditions for using the CLT are met. Find a 95% confidence interval for the proportion that express a great deal of confidence or quite a lot of confidence in the public schools, and interpret this interval.Please don't provide handwritten solution .....A poll reported that only 645 out of a total of 2029 adults in a particular region said they had a "great deal of confidence" or "quite a lot of confidence" in the public school system. This was down 5 percentage points from the previous year. Assume the conditions for using the CLT are met. Find a 95% confidence interval for the proportion that express a great deal of confidence or quite a lot of confidence in the public schools, and interpret this interval. The 95% confidence interval for the proportion that express a great deal of confidence or quite a lot of confidence in the public schools is ____
- I need help with creating a confidence interval using gender as a healthcare variableLast year, 535 out of 630 randomly selected U.S. firms tested their employees for drug use. Give a 99% confidence interval for the proportion of U.S. firms that do drug testing. Edit View Insert Format Tools Table A v ..Why do we need to compute a confidence interval rather than simply stating a point estimate?