Assume the values in your dataset are a sample from a larger population, even if that doesn't make sense for your application. Form a 95% confidence interval for the population proportion for this variable. Interpret your confidence interval for a business audience from the following results Count of Gender Row Labels Female Male Grand Total 56.67% 43.33% margin of error 1.46 100.00% sample porpotion 0.57 upper bound 2.03 lower bound -0.89
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- Find the critical t value to use in making an 80% confidence interval for a mean if the sample size is 35. Write your answer with 3 decimal places.a critic points out that this 95 % confidence interval is only accurate if the statistic follows a normal distrubution , or if the normal model is a good approximation. is this true for this data? explainconstruct a confidence interval for this data. You should construct a 95% confidence interval for this data. How you do this will depend on whether your data is summarized using a mean or proportions. If you have categorical data, you will have to pick one of the categories and focus on a confidence interval for the proportion for that category, and you only need to do one for that one category. Please show the parts of your equation (point estimate, Z or T, and standard error) in addition to your final result.
- Levels of insoluble ash (gm/kg) were measured ina sample of small (0.3 gm) aliquots of dried and groundalfalfa. Below are three confidence intervals for the mean: One is a 95% confidence interval, one is a 90% confidence interval, and the other is an 85% confidence interval. Without doing any calculations, match the inter-vals with the confidence levels and explain how you determined which interval goes with which level. Confidence levels: 95% 90% 85% Intervals (in scrambled order):(8.16, 10.88) (8.38, 10.66) (7.75, 11.29)In a random sample of 2500 men being treated for obesity, the mean total cholesterol level is 175 with a standard deviation of 25. Construct a 95% confidence interval around the mean and interpret it. Use the context of the question please.I chose Option 1 for this week’s discussion post. I want to estimate the population mean number of times adults between the ages of 30 and 45 went to the grocery store in the last week. I spoke with 12 adults and asked them how many times they went to the grocery store in the last week. The results were 0, 2, 2, 7, 5, 1, 0, 3, 1, 1, 4, and 3. Now calculate a 95% confidence interval for the population mean. (Round to three decimal places)
- In a survey, 32 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $49 and standard deviation of $7. Construct a confidence interval at a 98% confidence level. Please NOTE that the answer here has to be given in the form below sample mean +- margin of error, not the usual final answer bounds. > Next Question MacBook Pro @ # 2$ & 2 3 6 7 W E T Y S D G J この * 00Please answer the second part of the question. How should this value be related to the confidence level?Solve this attachment.
- A survey of 97 random homeowners in my neighborhood had a mean of $720 spent on lawn care. Construct a 98% confidence interval for the mean lawn care expenditure per household when the population variance is $400.You measure 20 backpacks' weights, and find they have a mean weight of 76 ounces. Assume the population standard deviation is 9.6 ounces. Based on this, construct a 99% confidence interval for the true population mean backpack weight. Give your answers as decimals, to two places + ouncesSuppose you want to produce an estimate on the percent of students who return to college after their first year. You are willing to tolerate a 2% margin of error at the 90% confidence level. What’s the minimum number of students that you need to keep the margin of error below 2%?