7.61 For the three-phase circult shown in Figure P7.61,find the current in the neutral wire and the real power.z= 11020Vj45 2Ty= 1102 2n/3 V-j20 2iв.Tg = 1102 41/3 V o

The three-phase circuit diagram is:

Answered: 7.61 For the three-phase circult shown…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

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The circuit shows an unbalanced electrical installation powered by a positive sequence symmetrical three- phase network of 380 V compound voltage. The loads are single phase. Load 1 absorbs an active power of 950 W with f.d.p. 0.5 inductive. Load 2 absorbs an active power of 1,140 W with f.d.p. Unit. Load 3 absorbs from the network an active power of 760 W with f.d.p. 0.5 capacitive. Taking the network voltage URN as the phase reference, calculate: a) complex expressions of the line currents IR. Is. and IT RO- SO- To- : IR Is IT UL-380 V CARGA 1 P₁ = 950 W cos p1=0,5 ind. CARGA 2 P₂=1.140 W cos p₂=1 CARGA 3 P3=760 W cos p3=0,5 cap.
How to solve for a (+) Phase Sequence and (-) Phase Sequence? Give an example and explain the steps.
How about the average power on each elements? And is it absorbing or delivering power too?
Consider the circuit shown in Figure 1. V1 is a 7.2 kHz sine wave with an amplitude of 4 V.Figure 1: RC Circuit Schematic1. Determine the total impedance (Z) of the circuit.2. Using V1 as a zero-phase reference, calculate the values of the following:a) Amplitude and phase of current (I)b) Amplitude and phase of voltage across R1 (VR1)c) Amplitude and phase of voltage across C1 (VC1
A load has a leading power factor. a) Is it a capacitive or inductive load? b) Is the reactive power positive or negative? c) Repeat for a load with lagging power factor
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Prob. I and Vc For the following RMS phasor circuit, a coworker has determined values for 50 Ohms 50 Ohms i,- 225 2253.13° = 190.92 + 254.56 VRMS R1 + R2 Vc = 237.17/26.565° = 212.13+ 106.07 VRMS 100 2 -3Z98.13° =-0.4243 + J2.970 ARMS C -j60 Ohms For this problem provide at least 3 digits of precision for the answers. The results for the following calculations are to be answered in - a) Find the current I b) Determine the real (P) and reactive(Q) power DELIVERED by the source c) Determine the real (P) and reactive (Q) power ABSORBED by each impedance ( resistors R1 and R2, inductor and capacitor). The values for P and Q can be positive or negative. Remember S =P+jQ, so do not include the j with your answer for Q. Each of these answers will require two parts. For the phasor a magnitude and angle will be needed. For the powers, The real power P and the reactive power Q are required.
The circuit shows an unbalanced electrical installation powered by a positive sequence symmetrical three- phase network of 380 V compound voltage. The loads are single phase. Load 1 absorbs an active power of 950 W with f.d.p. 0.5 inductive. Load 2 absorbs an active power of 1,140 W with f.d.p. Unit. Load 3 absorbs from the network an active power of 760 W with f.d.p. 0.5 capacitive. Taking the network voltage URN as the phase reference, calculate: a) complex expressions of the line currents IR. Is. and IT RO- SO TO IR Is IT U₁-380 V CARGA 1 P₁ =950 W cos p1=0,5 ind. CARGA 2 P₂=1.140 W cos p₂=1 CARGA 3 P3=760 W cos p3=0,5 cap.
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7.61 For the three-phase circult shown in Figure P7.61, find the current in the neutral wire and the real power. z= 11020V j45 2 Ty= 1102 2n/3 V -j20 2 iв. Tg = 1102 41/3 V o