7.) Carbocations are high energy intermediates in organic synthesis that are open-shelled carbon atoms. In the reaction below (a) we see that carbocations are also excellent Lewis acids, readily accepting a water molecule to form the product isopropanol. Given this, explain why when reaction (b) was set up, there were two regioisomeric products formed? Please draw a Lewis acid base reaction mechanism with arrows to justify your answer. H2O H OH a.) H3C CH3 H3C `CH3 carbocation Product open-shell H H20 H. OH H b.) H3C and H3C ČH3 ČH3 ČH3

7.) Carbocations are high energy intermediates in organic synthesis that are open-shelled carbon atoms. In the reaction below (a) we see that carbocations are also excellent Lewis acids, readily accepting a water molecule to form the product isopropanol. Given this, explain why when reaction (b) was set up, there were two regioisomeric products formed? Please draw a Lewis acid base reaction mechanism with arrows to justify your answer. H2O H OH a.) H3C CH3 H3C `CH3 carbocation Product open-shell H H20 H. OH H b.) H3C and H3C ČH3 ČH3 ČH3

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

9. What is the major organic product generated in the reaction sequence below? CI ďa (A) (B) -CI Br 1. K OtBu 2. Cl₂ (C) O ICI ㅎ........ (D)
2B Suggest a short synthetic route for the preparation of compound D from compound C OH Br COOH C D Note: Apart from compound C, you can also use organic reagents with up to 1 C atom. The number of arrows in the figure above does not necessarily correspond to the number of steps.
Paragraph 10. Answer ALL parts of this question. Treatment of acetylcyclopentane (see Scheme Q10a) with NaOEt in ethanol at 25 °C results in formation of a major, thermodynamic enolate (Scheme Q10a). NaOEt Thermodynamic enolate ELOH 25 °C (Scheme Q10a) (a) Draw the structure of the thermodynamic enolate. (b) Explain why the enolate in answer (a) is the major enolate present in the equilibrium at room temperature. (C) Draw the product formed when the thermodynamic enolate (1 mole) reacts with ethyl acrylate (1 mole) (Scheme Q10c). OEt + NaOEt Thermodynamic enolate Product ETOH 25 °C C12H2003 (Scheme Q10c) (d) Draw the kinetic product formed when 1-cyclopentene-1-carbaldehyde reacts with sodium cyanide at low temperature (5 °C) and over a short reaction time (5 minutes) (Scheme Q10d). NACN Kinetic product ELOH 5 °C (Scheme Q10d) >
• H2O Based on the reaction above, (a) Outline the reaction mechanism. (b) Sketch the energy diagram. (c) Give the rate equation. (d) Explain what happens to the reaction rate if: The leaving group is changed to I. (0) (a) The solvent is changed to DMF. The alkyl halide is changed to (v) The concentration of the solvent is increased by five-fold answer with proper justification and with good explanation
Q.6.
3) Fill in the red box(es) with the missing reactant(s), reagent(s), product(s), solvent, and/or conditions and write a reasonable mechanism for the reaction. Not every box needs to be used and not every box necessarily corresponds to only a single species. If no reaction occurs OR no reagents exist to perform the reaction state, "NOT POSSIBLE" AND explain why. Polymer HBr
(a) Tsomane and Nyiko were given a task of synthesising methylenecyclohexane 2. After a brief discussion with each other, Tsomane proposed Method A to synthesise 2 from cyclohexanone 1 while Nyiko proposed Method B that started from hydroxymethylcyclohexane 3. Each student believed that their proposed method is better than the other. (Scheme below) (1) Ph Ph 836 Ph THF A 1 B H₂SO4 100 °C 3 OH Which of the two methods (A or B) is more likely give high yield of methylenecyclohexane 2? Briefly explain.
Give explanation of the correct option and explanation of the incorrect options.
Blackboard 个→ X乙 Show Timer * Question Completion Status: (b). The alkyl halide 1-bromo-1,2-dimethylcyclohexane (A) undergoes dehydrohalogenation reaction when treated with methanol (CH3OH) as a nucleophile give a mixture of products, alkenes B and C. When the concentration of the alkyl halide is doubled, the rate of the reaction is doubles; the rate of product formation also doubles. However, when the concentration of the ethanol is doubled, the rate of the reaction is not affected (i) What is the mechanism responsible for this elimination reaction? (ii) Write the equation for the rate of the reaction (ii) Draw the structure of alkyl halide A
Please do question 4 for the reaction mechanism
Consider the reaction and answer the questions that follow. CH-CH2- CH2-I • CH,S° CH3- CH2- CH2-S– CH; + CH3-CH= CH2 Product A Product B O Explain which type or types of mechanisms (Sw1, SN2, E1, and E2) are applicable to this reaction. [") How can you increase the percentage of Product A? [ui) How can you obtain Product B as almost the only product? A. [i] SN2 & E2 [ii] Use better nucleophile [iii Use a non-nucleophilic base B. [i] SN2 & E2 [ii] Use higher Temperature [iii] Use a non- nucleophilic base C. [i] SN2 & E2 [ii] Use lower Temperature [iii] Use a non-nucleophilic base D. [i] SN1 & E1 [ii] Use lower Temperature [iii] Use a non-nucleophilic base
The following two sets of reactions [(a) and (b)] show possibilities for arrow pushing in individual reaction steps. Identify which is wrong and explain why. Then using the correct arrow pushing, label which molecule is the nucleophile and which is the electrophile. (b) H3C (a) i-CH3 + :F H3C C-CI: H3C--Ci: C-CH3 H3C H3C H3C .. H3C-CI :I-CHg + :Cl: :Cl: H3C H3C 1. C-CH3 C-C1: H3C H3C .. H3C