Please do question 4 for the reaction mechanism The document outlines three potential mechanisms for the bromination of trans-cinnamic acid. Each mechanism illustrates a different approach to the reaction, and all are feasible on paper. The task is to analyze each mechanism, determine the stereochemical outcome (syn, anti, or a mix), and draw the expected product.**Mechanism A:**- The diagram shows the trans-cinnamic acid molecule with a Br-Br bond approaching it.- There are no specific stereochemical details or further reaction steps provided in the diagram, suggesting that this is a simplified representation.**Mechanism B:**- The trans-cinnamic acid reacts with Br-Br.- A cyclic bromonium ion intermediate is formed.- The bromide ion attacks from the side opposite the existing bond, indicating an anti-addition.- This mechanism highlights the formation of a trans product due to the anti-attack.**Mechanism C:**- The first step shows the approach of Br-Br to trans-cinnamic acid, forming a bromonium ion with a positive charge on the bromine.- The bromide ion subsequently attacks from the side opposite the formed bromonium ion.- This results in the formation of the anti product, similar to Mechanism B, with the bromine atoms added on opposite sides of the molecule.In summary, each mechanism details a potential stereochemical pathway for the bromination of trans-cinnamic acid, with Mechanism B and C both resulting in anti-addition due to the bridging bromonium intermediate and subsequent attack by the bromide ion from the opposite side.

Syn addition means both the reagents come from the same side of the double bond and hence the stereochemistry of product is syn addition product as shown below:Carbocation is planar and nucleophile attacks either above or below the plane as shown below:Alkene reacts with bromine to give brominium ion. It reacts with bromide ion through anti-addition as shown below:The final aswer is shown below: