6. Using the following data, determine the difference in elevation between BM-15 and BM-16? Station BM-15 1 ·23. 4 5 BM-16 BS 4.64 5.80 3.25 6.02 3.86 4.03 FS 5.06 5.20 5.85 2.93 3.78 4.29 ELEV 209.65

6. Using the following data, determine the difference in elevation between BM-15 and BM-16? Station BM-15 1 ·23. 4 5 BM-16 BS 4.64 5.80 3.25 6.02 3.86 4.03 FS 5.06 5.20 5.85 2.93 3.78 4.29 ELEV 209.65

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Q.2 Reciprocal leveling was conducted across a wide river to determine the difference in level of…

Q: An ESP must treat 800,000 acfm with 99.1% efficiency. Assuming an effective drift velocity of 14…

A: Given: The discharge is 800,000 ft3/min. The efficiency is 99.1%. The effective drift velocity is 14…

Q: From the given differential leveling notes, compute the difference in elevation between stations 5…

Q: The simply supported beam loaded as shown in Figure 2 is made of W18 x 97. The uniform load that it…

A: Simply Supported Beam : A simply supported beam is having two supports each at end of the beam and…

Q: The sum of positive departures exceeds that of the negative departures by 0.47 meter. The sum of the…

A: Given data in question ∑D = 0.47 m ∑L=-0.67 m To find out Linear error of closure

Q: 6. There is a signaling tower on the top of a hill. In order to determine the elevation of the tower…

Q: Reduce the set of differential leveling notes in Table 2-11, and perform the arithmetic check.…

Q: LINE BEARING Determine the following: 1-2 S 73° 21' E (a) Interior Angle 2-3 S 40° 10' E (b)…

Q: 7.6 For the following consolidated drained triaxial tests on a clay, draw a p' versus q' diagram and…

A: Given data:Testp' (kN/m2)q' (kN/m2)128.7535.46238.3337.38373.7949.834101.664.25134.276.7Stress parth…

Q: 2. From the given profile leveling notes: STATION BS HI IFS FS BM1 1.543 3+100 0.557 3+200 1.353…

A: Calculate Reduced levels of each chainage?

Q: Two Pegs A and B were fixed on opposite banks of a 50 m wide river. The level was set up at A and…

A: Two pegs A and B were fixed on opposite banks of a 50 m wide river. The level was set up at A and…

Q: For all the computed values with decimals, use four (4) digits after the decimal. Differential…

A: Solution: Given data: Inclination angle =6°Average BS reading=3.15 mAverage length=300 mRecorded…

Q: 1. DIFFERENTIAL LEVELING STATION BACK SIGHT HEIGHT OF INSTR. FORESIGHT ELEVATION BM 10 4.64 209.65 m…

Q: Figure 2: 20KN 70° A 00 10 KN 3M 10.0 M IS KN X B 1.0M

Q: 10. Complete the following table using the knowledge obtained in class about differential leveling…

A: Given Data Total 5 stations has been given and we are asked to calculate the Elevations, adjusted…

Q: III. Differential Leveling 1. Complete the table below. STATION BM1 TP1 TP2 TP3 TP4 TP5 BM2 BS 2.11…

Q: From the given data of a differential leveling as shown in the tabulation: STA BS FS ELEV 1 5.87…

Q: y 5 kips/ft 6 ft FIGURE P7.45 9 kips/ft 2.5 m FIGURE P7.46 B 25 kN/m B 10 ft 4.0 m 11 ft 70 kN/mm C…

Q: A.) Determine the difference in elevation between TP1 and TP3

A: Profile leveling is used to determine the elevation of various locations along a line at a uniform…

Q: Q3) From the figure below Compute :- 1)Elevation of point B 2)Elevation of point C 3)Height of the…

Q: 15 kN/m Zoom image Bour 3 m 3m CH 20 kN 3 m D

Q: From the given leveling notes, compute the elevation of BM2 ELEVATION OF BM1 IS EQUAL TO 149.20

A: Given:- Station BS HI FS Elevation BM1 0.57 TP1 1.15 2.93 TP2 0.65 2.70 TP3…

Q: Show step by step solution

A: Answer to this question is given below.Explanation:

Q: STA. B.S. F.S. 1 5.87 2 7.03 6.29 3 3.48 6.25 4 7.25 7.08 5 10.19 5.57 6 9.29 4.45 7 4.94 For…

A: Lets using Rise/Fall method B.S - F.S = Rise/Fall Positive difference mean rise Negative…

Q: omplete the table of information and calculate the difference in elevation of ation 0+ 020 and…

A: HERE BS FS AND IS ARE GIVEN .RL IS ALSO GIVEN THATS IS 200

Q: From the following differential leveling notes, compute the difference in elevation between stations…

A: Data for the Differential leveling is given in the question

Q: 0.9 (IFS) 1.7 (IFS) 3.43 TP1 2.77 (BS) (FS) 2.32 (BS) BM1 EL. 328.70m 2.2 (IFS) BM2 2.45 3.7 (FS)…

A: Given question belongs to levelling topic. Here the back sight , intermediate fore sight and…

Q: Complete the following level notes. Show your detailed solution and checking. Differential…

Q: A line was measured three times and yield the following results; 856.42, 856.69 and 856.12 m.…

A: Answer Probable error of the mean is given by Em = Esn Es = Probable error of a single measurement…

Q: er. Linear error of closure is:

Q: Width U/S of dam = 45.7 , length of spillway = 14.2 , head above crest = 14.9 %3D %3D if approach…

A: A dam is a pressure driven design of genuinely impenetrable material worked across a waterway to…

Q: 10 m B 60 KN 40 KN 80 KN 30 m 50m- 50m 30m

Q: 1. Determine the elevation at each station. STATION BS HI FS BM1 1.285 TP1 2.314 2.345 TP2 1.562…

A: Given data:

Q: Calculate the a.) Double deflection Integration b.) Area- Moment at point E Method Method c.)…

A: NOTE : Since you have asked multiple methods we will solve the first method for you. If you want any…

Q: The sum of negative departures exceeds that of the positive departures by 0.47 meter. The sum of the…

Q: A dumpy level is setup at one end of a line 120m long for the purpose of determining the…

A: The stadia interval factor is given by, k=Ds where D = horizontal distance s = stadia intercept…

Q: en TP1 and TP2. Assume stadia interval factor equal to 100 and instrument constant equal to zero.…

Q: 534.158 m , 462.257 m, DAB 1, XA VA = 104.321 m, aAB = 45°32'48". Ув %3D AxaB = ? AyAB = ? xg = ? yB…

A: ΔXAB =DAB ×cosαAB ΔyAB =DAB ×sinαAB ΔxB =ΔxA +ΔxAB ΔyB =ΔyA +ΔyAB ΔxA=534.158 m ΔyA…

Question

6. Using the following data, determine the difference in elevation between BM-15 and BM-16?
Station
BM-15
1
·23.
4
5
BM-16
BS
4.64
5.80
3.25
6.02
3.86
4.03
FS
5.06
5.20
5.85
2.93
3.78
4.29
ELEV
209.65

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

G
For all the computed values with decimals, use four (4) digits after the decimal.
Refer to the given table of differential leveling, find the value of A find the value of B (m) find the Value of C (m)
A level is set up at a point 140 m from A and 110 m from B; the observed staff readings at A and B are 2.255and 1.575 respectively. The true difference of level between A and B is 0.6691 0.6795 0.6882 0.6800
Draw a sketch of level rods (as seen from the eyepiece of an engineer's transit) with the following measurements. i. ii. iii. 2.265 m 1.442 m 2.418 m iv. 3.415 m Example:
Question 49 In leveling across a river, reciprocal level readings were taken between two points A and B. From a set up near A: on A, 0.994 and 0.992 m; on B 2,076, 2.077, 2.078 and 2.077 m. At the set up near B: on H, 2.550 and 2.548m; on A, 1.462, 1.463, 1.464 and 1.463. From the observed data it can be determine that A. B is 1.085 m below A B. B is 1.085 m above A C. A is above B by 1.088 m D. A is below B by 1.084 m E. A and B are of the same elevation
Answer with detailed solution
Draw a sketch of level rods (as seen from the eyepiece of an engineer's transit) with the following measurements. i. ii. 2.275 m 1.772 m ii. 3.715 m iv. 0.250 m v. 2.718 m Example: DS
From the given data of a differential leveling as shown in the tabulation: STA. B.S. H.I. F.S. ELEV. A 5.87 329.25 7.03 6.29 3.48 6.25 D 7.25 7.08 E 10.19 5.57 9.29 4.45 G 4.94 a.) Find the difference in elevation of station F and station E. b.) Find the difference in elevation of station G and station B. c.) Find the elevation of station D.
From the given profile leveling notes: What is the difference in elevation between station 5 and 2? * Profile Leveling Notes Station BS FS IFS Elev BM1 0.95 255.50m 1 3.00 2 2.30 TP1 3.13 0.64 3 2.70 4 2.80 3.10 0.50 7 0.80 TP2 2.16 1.28 8. 0.90 9. 1.20 10 1.70 11 2.80 ТРз 0.82 2.37 TP4 1.35 3.50 12 3.00 BM2 1.24 1.60 m 3.10 m 2.30 m 0.59 m