6. There is a signaling tower on the top of a hill. In order to determine the elevation of the tower top Q. observations were made from two stations P and R. Points P, Q and R lie in the same plane. If angles of elevation of the top point Q from P and R are respectively 24° 30' and 14° 37'. Determine the elevation of foot of tower of signal tower height is 4 m. The staff readings on BM of RL 100 m are 2.085 m and 3.455 m respectively from instrument located at P and R. Distance between P and R is 125 m.

6. There is a signaling tower on the top of a hill. In order to determine the elevation of the tower top Q. observations were made from two stations P and R. Points P, Q and R lie in the same plane. If angles of elevation of the top point Q from P and R are respectively 24° 30' and 14° 37'. Determine the elevation of foot of tower of signal tower height is 4 m. The staff readings on BM of RL 100 m are 2.085 m and 3.455 m respectively from instrument located at P and R. Distance between P and R is 125 m.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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a) 0.700 The following readings were taken in sequence during a leveling job: Readings (m) 1.250 1.285 1.125 0.810 1.555 -1.400 1.235 0.665 1.905 Remarks BMI R.L. = 101.335 Peg A Peg B 2 Change Point CP2 Change Point CP2 BM2 R.L=103.879 -1.400 Change Point CP1 Change Point CP1 CGS 1905 Inverted staff reading taken to the underside of a bridge Peg C Prepare a standard form of booking for these readings and reduce them using the rise fall method applying all the necessary arithmetic checks and adjust the final Reduced Levels.
Solve for this prob. Formula: H.I. = Elevation of given B.M. + B.S. Elevation of T.P. = H.I. – F.S. Ground Elevation at Centerline Station = H.I. – I.F.S. Error of Closure (e) = SB.S - SF.S. Error of Closure = Elev B.M. – Elev. of the last point
Q.1 A line of level is run from B.M .1 (elevation=102.00m) to B.M. 2(elevation=106.00m). The field observations were recorded as given below: Station В. S I.S F. S Remarks 1 1.95 В.М. 1 2 0.65 2.60 1.45 4 -1.90 -1.60 5 0.55 6 0.50 В.М. 2 Reduce the level of point 2, 3, 4 and 5, determine the total error of closure, and adjust the values.
The differential level notes is shown below. The elevation of the reference station (BM-100) is 100.709 meters above mean sea level. STA BS HI FS ELEVATION BM-100 2.856 ТР-1 3.230 1.285 ТР-2 3.096 0.688 TP-3 4.059 0.525 ТР-4 3.845 1.980 ТР-5 3.553 2.320 ТР-6 2.894 2.552 BM-200 3.123 a.) Complete the columns for Height of the Instrument (HI) and Elevation of the table above. b.) What is the elevation of BM-200 and its difference in elevation from station BM-100? c.) What is the highest station and its elevation?
The two points 1 and 2 are spaced at a horizontal distance of 243.22 m. The elevation of point 1 is 911.46 m and that of point 2 is 903.37 m. Then, the gradient from point 1 to point 2 in percent % is : Finish attempt ... Jump to... Surveying Lecture 07-03-... 2.
Q.1 A line of level is run from B.M.1 (elevation=106.40m) to B.M. 2(elevation=110.50m). The field observations were recorded as given below: Station В. S I.S F.S Remarks В.М. 1 1 1.95 0.65 2.60 1.45 -1.90 -1.60 5 0.55 0.50 В.М. 2 Reduce the level of point 2, 3, 4 and 5, determine the total error of closure, and adjust the values.
The following level notes for the determination of BM#2 do not check. The elevation of BM#1 and the rod readings are correct. Determine the corrected elevation of BM#2. STA B.S. H.I. F.S. ELEV. BM 1 6.72 127.36 120.64 TP 1 12.43 138.55 1.24 126.12 ТР 2 2.65 140.09 1.11 137.44 TP 3 0.54 132.59 8.04 132.05 ТР 4 4.27 124.55 12.31 120.28 BM 2 3.02 121.33
Q- The levelling staff held at a distance of 200 m is read at 4.54 m with the bubble out of centre by 2 divisions towards the observer. If the sensitiveness of the bubble is 25 secs/division, and 1 division = 2 mm, then actual staff reading must have been..
pls help me solve this. 1) a transit with stadia interval factor of 100.8 was set up at point C on the line bet. A and B. The ff. readings were observed: (*see from attached photo) If the distance from the focus is 0.38m. determine the ff.: a) horizontal distance bet. A and B b) Diff. in elevation bet. A and B of the value of HI are 300m and 315m respectively.
A straight road is heading N 24° W. A man driving on the road observes that at a point A on the road, an observation tower is located at 34° E of N. When he reach point B on the road, 1000 m from A, he observed that the tower is now located 53°E of S. Estimate the shortest distance from the tower to the road. A. 515.12 m С. 319.75 m D. 411.82 m В. 214.95 m
Three points on the ground were established such that point C is the point where the theodolite was set. A subtense bar were sighted at point A to be 00°18' and at point B is 00°19'30". If the horizontal angle was read between points A and B to be 38°45', find the distance AB. ps. please i need answer ASAP?
SON/m A 9m lom 12m 12m Determine the vesultant farce (R) and indieste its location from point (B)