6. Suppose X is a random variable with E(X) = 4 and Var(X) = 9. Let Y = 4X + 5. Compute E and Var(Y). Select one: O a. none O b. 69 O c. 176 O d. 144
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- An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails" (t) which we write hth, ttt, etc. For each outcome, let N be the random variable counting the number of tails in each outcome. For example, if the outcome is hth, then N (hth) = 1. Suppose that the random variable X is defined in terms of N as follows: X=2N² -6N-1. The values of Xare given in the table below. Outcome thh tth hhh hth ttt htt hht tht Value of X -5 -5 − 1 -5 −1 -5 -5 -5 Calculate the probabilities P(X=x) of the probability distribution of X. First, fill in the first row with the values of X. Then fill in the appropriate probabilities in the second row. Value X of X P(X=x) 0 8 XAn ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails" (t) which we write hth, ttt, etc. For each outcome, let N be the random variable counting the number of heads in each outcome. For example, if the outcome is thh, then N (thh)=2. Suppose that the random variable X is defined in terms of N as follows: X=2N²-6N-4. The values of X are given in the table below. ttt hhh hth hht tht htt thh tth Value of X -4 -4 -8-8-8-8-8-8 Outcome Calculate the probabilities P (X=x) of the probability distribution of X. First, fill in the first row with the values of X. Then fill in the appropriate probabilities in the second row. Value x of X P(X=x) 7 00 X S2. Let X be the mean of a random sample of n = 25 from N(30, 9). Find the probability that the sample mean is between 29.8 and 30.6.
- An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails" (t) which we write hth, ttt, etc. For each outcome, let N be the random variable counting the number of heads in each outcome. For example, if the outcome is hhh, then N (hhh) = = 3. Suppose that the random variable X is defined in terms of N as follows: X=6N-2N²-3. The values of X are given in the table below. Outcome hhh hth hht thh htt tth ttt tht Value of X-3 1 1 1 1 1 -3 1 Calculate the probabilities P (X=x) of the probability distribution of X. First, fill in the first row with the values of X. Then fill in the appropriate probabilities in the second row. Value X of X P(X=x) 0 0 0 00 XVSC Type here to search F1 W TE R Boys Not boys Juniors 65 35 Not juniors 220 145 Total 285 180 465 1. What is the probability that a student selected at random is a boy? PB + )= 285/465 2. What is the probability that a boy selected at random is a Junior? P(| J|B)= 65/285 3. What is the probability of randomly choosing a student who is a Junior and a boy? P(JB) WOMENGEN 65/465 4. What is the probability of randomly choosing a student who is a girl given that she is not junior? P(| G|J = 145/365 5. What is the probability of randomly selecting a girl? P(G) = 180/965 31 ( 99+ F5 1. I T Y F2 F3 1² 1 Total % 100 365 My Apps Dashboar... 220 F6 F7 F8 1'. 1'. 65 F9 35 Cip F10 ETE 145 F11 F12 4- BackspaceAn ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails" (t) which we write hth, ttt, etc. For each outcome, let N be the random variable counting the number of tails in each outcome. For example, if the outcome is tth, then N (tth)=2. Suppose that the random variable X is defined in terms of N as follows: X=N²-2N-2. The values of X are given in the table below. Outcome ttt htt hhh tht tth hth hht thh Value of X 1 -2 -2 -2 -2 -3 -3 -3 Calculate the probabilities P (X=x) of the probability distribution of X. First, fill in the first row with the values of X. Then fill in the appropriate probabilities in the second row. Value X of X P(X=x) 0 0 0 0 0 00 X Ś
- There are 5 black, 3 white, and 4 yellow balls in a box (THE SAME BOX as seen in the previous question). Four balls are randomly selected without replacement. Let Y be the number of yellow balls selected. Find P[Y =2]. 5 3 в w О а. About 21% O b. About 25% С. About 34%. d. About 9.3% e. About 13%An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails" (t) which we write hth, ttt, etc. For each outcome, let N be the random variable counting the number of tails in each outcome. For example, if the outcome is hth, then N (hth) = 1. Suppose that the random variable X is defined in terms of N as follows: X=2N² − 6N-1. The values of X are given in the table below. Outcome thh tth hhh hth ttt htt hht tht Value of X-5 -5 -1 -5 -1 -5 -5 -5 Calculate the probabilities P(X=x) of the probability distribution of X. First, fill in the first row with the values of X. Then fill in the appropriate probabilities in the second row. Value X of X P(X=x) 0 0 00 X13) A player spins two spinners. The outcome of each spinner is 1, 2, or 3. Each outcome is equally likely. Define the random variable X to be the maximum of the two numbers on the spinners. What is E[X]? a. 2/3 b. 5/3 c. 20/9
- An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails" (t) which we write hth, ttt, etc. For each outcome, let R be the random variable counting the number of heads in each outcome. For example, if the outcome is tth, then =Rtth1. Suppose that the random variable X is defined in terms of R as follows: =X−R2−3R4. The values of X are given in the table below. Outcome htt tht hth thh ttt hhh hht tth Value of X −6 −6 −6 −6 −4 −4 −6 −6 Calculate the values of the probability distribution function of X, i.e. the function p X. First, fill in the first row with the values of X. Then fill in the appropriate probabilities in the second row.Q. 1 Deal two cards from a well-shuffled deck of cards. Let the random variable X be the number of aces dealt and let the random variable Y be the number of face cards dealt. (i) Find and sketch fx.y (x, y).
