For each outcome, let IV be the random variable counting the number of tails in each outcome. For example, if the outcome is hth, then N (hth) that the random variable X is defined in terms of N as follows: X=2N² -6N-1. The values of X are given in the table below. Outcome thh tth hhh hth ttt htt hht tht Value of X -5 -5 -1 -5 -1 -5 -5 -5 Calculate the probabilities P(X=x) of the probability distribution of X. First, fill in the first row with the values of X. Then fill in the appropriate probabilities the second row. Value X of X P(X=x) 0 1. Suppos 0 0
For each outcome, let IV be the random variable counting the number of tails in each outcome. For example, if the outcome is hth, then N (hth) that the random variable X is defined in terms of N as follows: X=2N² -6N-1. The values of X are given in the table below. Outcome thh tth hhh hth ttt htt hht tht Value of X -5 -5 -1 -5 -1 -5 -5 -5 Calculate the probabilities P(X=x) of the probability distribution of X. First, fill in the first row with the values of X. Then fill in the appropriate probabilities the second row. Value X of X P(X=x) 0 1. Suppos 0 0
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails" (t) which we write hth, ttt, etc.
For each outcome, let N be the random variable counting the number of tails in each outcome. For example, if the outcome is hth, then N (hth) = 1. Suppose
that the random variable X is defined in terms of N as follows: X=2N² − 6N-1. The values of X are given in the table below.
Outcome thh tth hhhhth ttt htt hht tht
Value of X-5 -5 -1 -5 -1 -5 -5 -5
Calculate the probabilities P(X=x) of the probability distribution of X. First, fill in the first row with the values of X. Then fill in the appropriate probabilities in
the second row.
Value X of X
P(X=x)
0 0
00
X
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