An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails" (t) which we write hth, ttt, etc.For each outcome, let N be the random variable counting the number of tails in each outcome. For example, if the outcome is hth, then N (hth) = 1. Supposethat the random variable X is defined in terms of N as follows: X=2N² − 6N-1. The values of X are given in the table below.Outcome thh tth hhh hth ttt htt hht thtValue of X-5 -5 -1 -5 -1 -5 -5 -5Calculate the probabilities P(X=x) of the probability distribution of X. First, fill in the first row with the values of X. Then fill in the appropriate probabilities inthe second row.Value X of XP(X=x)0 000X

The objective of the question is to calculate the probabilities P(X=x) of the probability…

Answered: An ordinary (fair) coin is tossed 3…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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If x is functionally related to A and B as x = A + B, and if A and B are random variables, then x is also a random variable. True or False
An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails" (t) which we write hth, ttt, etc. For each outcome, let N be the random variable counting the number of tails in each outcome. For example, if the outcome is hht, then = Nhht1. Suppose that the random variable X is defined in terms of N as follows: =X−2N2−4N3. The values of X are given in the table below. Outcome ttt hhh htt hht thh tht hth tth Value of X 3 −3 −3 −5 −5 −3 −5 −3 Calculate the probabilities P (X = x) of the probability distribution of X. First, fill in the first row with the values of X. Then fill in the appropriate probabilities in the second row. Value x of X P (X = x)
just this multichoice question please
An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails" (t) which we write hth, ttt, etc. For each outcome, let N be the random variable counting the number of heads in each outcome. For example, if the outcome is ttt, then N (ttt) = 0. Suppose that the random variable X is defined in terms of N as follows: X = 2N−2N2 - 1. The values of X are given in the table below. Outcome ttt hht tth htt hhh tht hth thh Value of X −1 −5 −1 −1 −13 −1 −5 −5 Calculate the probabilities P (X = x) of the probability distribution of X. First, fill in the first row with the values of X. Then fill in the appropriate probabilities in the second row. Value x of X P (X = x)
In large corporations, an "intimidator" is an employee who tries to stop communication, sometimes sabotages others, and, above all, likes to listen to him or herself talk. Let x1 be a random variable representing productive hours per week lost by peer employees of an intimidator. x1: 7 4 7 2 2 5 2 A "stressor" is an employee with a hot temper that leads to unproductive tantrums in corporate society. Let x2 be a random variable representing productive hours per week lost by peer employees of a stressor. x2: 3 3 10 7 6 2 5 8 (i) Use a calculator with sample mean and sample standard deviation keys to calculate x1, s1, x2, and s2. (Round your answers to two decimal places.) x1 = s1 = x2 = s2 = (ii) Assuming the variables x1 and x2 are independent, do the data indicate that the population mean time lost due to stressors is greater than the population mean time lost due to intimidators? Use a 5% level of significance. (Assume the population distributions of time…
An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails" (1) which we write hth, ttt, etc. For each outcome, let N be the random variable counting the number of heads in each outcome. For example, if the outcome is htt, then N (htt) = 1. Suppose that the random variable X is defined in terms of N as follows: X=2N-N2 -4, The values of X are given in the table below. Outcome hht tth hth thh tht ttt hhh htt Value of x -4 -3 -4 -4 -3 -4 -7 -3 Calculate the probabilities P(X=*) of the probability distribution of X. First, fill in the first row with the values of X. Then fill in the appropriate probabilities in the second row. Value of x _ _ _ p(X=x) _ _ _
An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails" (t) which we write hth, ttt, etc. For each outcome, let N be the random variable counting the number of tails in each outcome. For example, if the outcome is hth, then N (hth) = 1. Suppose that the random variable X is defined in terms of N as follows: X=2N² -6N-1. The values of Xare given in the table below. Outcome thh tth hhh hth ttt htt hht tht Value of X -5 -5 − 1 -5 −1 -5 -5 -5 Calculate the probabilities P(X=x) of the probability distribution of X. First, fill in the first row with the values of X. Then fill in the appropriate probabilities in the second row. Value X of X P(X=x) 0 8 X
In each of the examples that follow, determine what value the random variable would assign to the specific outcome listed. You have some number of coins in your pocket, and you choose two at random. The random variable ZZ assigns the value of the coins in cents to each outcome. What value is assigned when you draw out a quarter and a dime? A coin is flipped three times. YY is a random variable that assigns 3 times the number of heads flipped minus 2 times the number of tails flipped. What number is assigned to HHT? A person picks a number between 1 and 272820. The random variable ZZ assigns the 0 to an even number and 1 to an odd number. What number is assigned to 270221?
Dispatches to the Miami Coast Guard Search & Rescue Division concern either routine or emergency cases. The time to process a routine case is an exponential random variable with an expected value of 3 minutes, while the time to process an emergency case is an exponential random variable with an expected value of 10 minutes. A dispatch is routine with a probability of 0.8, or an emergency with a probability of 0.2. The status of dispatches and processing times are independent across dispatches. Let X be the processing time of the next dispatch. a) Calculate P{X > 4}.b) Calculate E[X].c) Calculate Var(X). (Hint: Var(X) = E[Var(X |Y )] + Var(E[X |Y ]).
Consider the following random experiment: we toss a two-sided coin (H on one side and T on the other side) n = 3616 times. In any given toss, the probability the coin comes up H is p = P(H) = 0.3. Each time the coin comes up H we give Tom 2 dollars and each time the coin comes up T we take from Tom 1 dollar (so Tom either gets 2 or gets -1, i.e., loses 1 dollar). How many dollars do we expect Tom will get on "average", i.e., per experiment?
These questions concerns the following situation. There is a rain on a football ground. The ground is 100 meters long and 70 meters wide. Model the event of a raindrop falling as a randomly selected point in the rectangle pictured.Lets imagine the following random variables: X is the x-coordinate where a raindrop falls, Y is the y-coordinate of where a raindrop falls, and Z=X+Y. CHOOSE ONE AND SHOW THE PROCESS. Which one of the following statements are true? * a) X and Y are independent b) X and Z are independent c) Y and Z are independent
An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails" (t) which we write hth, ttt, etc. For each outcome, let N be the random variable counting the number of heads in each outcome. For example, if the outcome is thh, then N (thh)=2. Suppose that the random variable X is defined in terms of N as follows: X=2N²-6N-4. The values of X are given in the table below. ttt hhh hth hht tht htt thh tth Value of X -4 -4 -8-8-8-8-8-8 Outcome Calculate the probabilities P (X=x) of the probability distribution of X. First, fill in the first row with the values of X. Then fill in the appropriate probabilities in the second row. Value x of X P(X=x) 7 00 X S

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