A random variable X can take on only three values: 1, 3 and 0. X takes value 1 with probability and value 0 with remaining probability. What is the mean of X, , value 3 with probability E[X]? 25/12 3 4/3 9/4 5/2 2
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Given that
Probability mass function of X is
x | 0 | 1 | 3 |
P(x) |
1/12 |
1/4 | 2/3 |
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- Could you help with this quesiton about random variables?Qn 2 use z table no excelAn ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of “heads” (h) and “tails” (t) which we write hth, ttt, etc. for each outcome let R be the random variable counting the number of heads in each outcome. For example, if the outcome is hhh, then R (hhh)=3. Suppose that the random variable X is defined in terms of R as follows: X= 2R-2R^2-3. The values of X are given in the table below.
- When v, = 2, show that the significance level of F corresponding to a significant probability p is: F = [p-(2/₂) - 1] where v, an v₂ have their usual meanings. V2 2Suppose X is a random variable with X - N(90, 52) and let u = the mean of X me = the median of X mo = the mode of XAn ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails" (t) which we write hth, ttt, etc. For each outcome, let R be the random variable counting the number of heads in each outcome. For example, if the outcome is hth, then =Rhth2. Suppose that the random variable X is defined in terms of R as follows: =X−2R1. The values of X are given in the table below. Outcome tth thh hht htt ttt hhh hth tht Value of X 1 3 3 1 −1 5 3 1 Calculate the values of the probability distribution function of X, i.e. the function pX. First, fill in the first row with the values of X. Then fill in the appropriate probabilities in the second row. Value x of X pXx
- An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (h) and "tails" (t) which we write hth, ttt, etc. For each outcome, let N be the random variable counting the number of tails in each outcome. For example, if the outcome is hth, then N (hth) = 1. Suppose that the random variable X is defined in terms of N as follows: X=2N² -6N-1. The values of Xare given in the table below. Outcome thh tth hhh hth ttt htt hht tht Value of X -5 -5 − 1 -5 −1 -5 -5 -5 Calculate the probabilities P(X=x) of the probability distribution of X. First, fill in the first row with the values of X. Then fill in the appropriate probabilities in the second row. Value X of X P(X=x) 0 8 XIf the variance of X is 0 then the covariance between X and Y O is equal to 1 O is equal to -1 O cannot be determined O is equal to 0 O is equal to the variance of Y. O None of the AboveStep 7 (d) Compute u, the expected value of the number of fish caught per fisherman in a 6-hour period. Recall that the expected value is calculated using the formula u = xP(x), where x is the value of a random variable, P(x) is the probability of that variable, and the sum is taken for all values of the random variable. First determine xP(x), the product of x and P(x), for each value of x (let x = 4 for the value of "4 or more"). 1 3 4 or more P(x) 0.46 0.33 0.17 0.03 0.01 1(0.33) 0(0.46) ХP(x) = 0 Submit Skip (you cannot come back). Need Help? Read It Viewing Saved Work Revert to Last Response Submit Answer Submit Assignment Save Assignment Progress
- I need help part b please. Is the integral from 9.2 or 9.32. Let X be a random variable with p.m.f., (1+ x? f(x) = -,x = -1,0,1,2,3 20 0 ,otherwise. Find E(3X2 + 6).Let X be a random variable that takes values from 0 to 9 with equal probability 1/10. Find the probability distribution of the random variable Y = 6 mod (X + 1)