6.Choose the compound that will produce the spectrum below and assign the signals as carbonyl, aryl, or alkyl.100ō (ppm)5007.200150Assign all of the protons on the spectrum below.8.AB4EC3ō (ppm)210Choose the compound that will produce the spectrum below and assign the signals to the correspondingprotons.OH6OH32104ō (ppm)

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Answered: 6. Choose the compound that will…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Please explain how to use DEPT spectra.
Attached is the 1H NMR spec for phenylethylamine. Draw the structure of the amine on the spectrum, and identify each peak (e.g. a labeled H atom on your structure, TMS, etc.)
5. Tyrosine is an important amino acid in Biochemistry. Assign the peaks in the 'H-NMR to the hydrogens in the structure of tyrosine by placing a, b, c, and d in the appropriate corresponding boxes. The hydrogen atoms attached to O and N atoms do not need to be labeled on this spectrum. с 11 10 16 00 a H. H- H H -*|| NH₂ Tyrosine d -H ppm
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Hi can you help me find the chemical reaction and molecular structure of this Nmr.
A 13C NMR spectrum is shown for a molecule with the molecular formula of C4H8O2. Draw the structure that best fits this data.
Connections to biology 5. Tyrosine is an important amino acid in Biochemistry. Assign the peaks in the ¹H-NMR to the hydrogens in the structure of tyrosine by placing a, b, c, and d in the appropriate corresponding boxes. The hydrogen atoms attached to O and N atoms do not need to be labeled on this spectrum. b 14 12 10 d HN C NH₂ histidine PPM OH
2. (Chapter 13 - Q58b) The compound whose H NMR spectrum is shown has the molecular formula C7H7B1. Follow the following questions to predict the unknown structure. Chem. shift Rel. area 2.31 1.50 701 1.00 7.35 1.00 TMS 10 7 6 O ppm 4 3 2 Chemical shift (8) e20s Cenge leaming 2(a) Degree of the unsaturation of this compound is= 2(b) The two distinct peaks in the aromatic region of the H NMR indicate that compound is .disubstituted = 2(c) The splitting pattern of the peak at 2.31 ő is = 2(d) The group that corresponds to the splitting pattern in 1(c) is = 2(e) This compound has the plane of symmetry Yes or No = 2(f) The name of the unknown compound = Intensity
Compound CsH12 gives the following H-NMR. Draw the structure of the compound. Draw a box around the structure you want graded. 5.00 1.00 6.04 70 6.5 6.0 4.0 3.5 3.0 25 20 1.5 A student was adding bromine across the double bond of 2-butene to make 2,3-dibromobutane. After taking the NMR, the student discovered they didn't get the product expected. Based on the NMR, what product did they obtain? Draw a box around your answer. 1.00 2.01 |2.00 3.00
Ha, Hb, Hc, Hd or cant tell
Assign all of the signals in the ¹H NMR spectrum for propyl acetate. Fill in the table below with the 'H NMR data. Number each proton (or set of protons) to match the corresponding peak in the NMR. Integration Splitting Propyl acetate structure with protons labeled Signal - Chemical shift (ppm) 1 2 3 4 11 propyl acetate 10 9 8 7 6 5 ppm 2H, triplet 4 3 3H, singlet 3H, triplet 2H, sextet 2 1 Figure 3.7 ¹H NMR spectrum for propyl acetate. 0
11. The proton NMR spectrum for a compound with formula C,HgO is shown below. The normal carbon-13 NMR spectrum has five peaks. The infrared spectrum has a strong band at 1746 cm. The DEPT-135 and DEPT-90 spectral results are tabulated. Draw the structure of this compound. Normal Carbon DEPT-135 DEPT-90 44 ppm Negative No peak ( 125 Positive Positive 127 Positive Positive CA 138 No peak No peak co 215 No peak No peak Proton spectrum C,HgO uluw 0.0 4.10 0.5 4.14 1.0 1.5 2.0 2.5 3.0 3.5 7.5 4.0 70 4.5 6.5 6.0 5.5 5.0

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