2. (Chapter 13 - Q58b) The compound whose H NMR spectrum is shown has the molecular formula C7H7B1. Follow the following questions to predict the unknown structure. Chem. shift Rel. area 2.31 1.50 701 1.00 7.35 1.00 TMS 10 7 6 O ppm 4 3 2 Chemical shift (8) e20s Cenge leaming 2(a) Degree of the unsaturation of this compound is= 2(b) The two distinct peaks in the aromatic region of the H NMR indicate that compound is .disubstituted = 2(c) The splitting pattern of the peak at 2.31 ő is = 2(d) The group that corresponds to the splitting pattern in 1(c) is = 2(e) This compound has the plane of symmetry Yes or No = 2(f) The name of the unknown compound = Intensity

2. (Chapter 13 - Q58b) The compound whose H NMR spectrum is shown has the molecular formula C7H7B1. Follow the following questions to predict the unknown structure. Chem. shift Rel. area 2.31 1.50 701 1.00 7.35 1.00 TMS 10 7 6 O ppm 4 3 2 Chemical shift (8) e20s Cenge leaming 2(a) Degree of the unsaturation of this compound is= 2(b) The two distinct peaks in the aromatic region of the H NMR indicate that compound is .disubstituted = 2(c) The splitting pattern of the peak at 2.31 ő is = 2(d) The group that corresponds to the splitting pattern in 1(c) is = 2(e) This compound has the plane of symmetry Yes or No = 2(f) The name of the unknown compound = Intensity

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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3. (Chapter 13 - Q58c) The compound whose H NMR spectrum is shown has the molecular formula C3H9B1. Follow the following questions to predict the unknown structure. Chem. Rel. shift area 3.16 1.00 3.56 1.00 1.00 1.50 Z18 729 TMS 10 O ppm Chemical shift (8) ng 3(a) Degree of the unsaturation of this compound = 3(b) The two peaks at 3.16 8 and 3.56 ő indicate two triplets Yes or NO = 3(c) The compound has 2 CH2 groups Yes or No = 3(d) Depending on the two triplets' chemical shifts one of the CH2 may have attached to the Br, Yes or No = 3(e) The multiplet at 7.18 õ to 7.29 õ indicate that compound is. disubstituted benzene - 3(f) The name of the unknown compound is = Intensity