1. (Chapter 13 - Q57) The H and 1C NMR spectra of compound A, CaH9Br are sho below. Answer the following questions. Chem. Rel. shift area 1.20 3.00 2.58 2.00 2.00 2.00 707 7.39 TMS 10 O ppm 4 Chemical shift (8) TMS 200 180 160 140 120 100 Chemical shift (8) O ppm 20 1(a) Degree of the unsaturation of this compound is - 1(b) The derived unsaturation number indicates that compound has . a(c) Two peaks in between 6.5 - 8.0 0 indicate that compound is 1(d) According to the splitting pattern of the peak at 1.20 d and 2.58 ð indicates that compound has a. - group= 1(e) According to the H NMR spectrum the number of nonequivalent aromatic prot sets in the compound - 1(1) According to the 19C NMR, the number of nonequivalent carbons in the compou 1(g) According to your answer in Q 1(f) the compound has a plane of symmetry Yes a NO = 1(h) The IUAC name for this unknown compound is = Intensity- Intensity

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1. (Chapter 13 - Q57) The H and 1C NMR spectra of compound A, CaH9Br are sho
below. Answer the following questions.
Chem. Rel.
shift area
1.20 3.00
2.58 2.00
2.00
2.00
707
7.39
TMS
10
O ppm
4
Chemical shift (8)
TMS
200
180
160
140
120
100
Chemical shift (8)
O ppm
20
1(a) Degree of the unsaturation of this compound is -
1(b) The derived unsaturation number indicates that compound has .
a(c) Two peaks in between 6.5 - 8.0 0 indicate that compound is
1(d) According to the splitting pattern of the peak at 1.20 d and 2.58 ð indicates that
compound has a.
- group=
1(e) According to the H NMR spectrum the number of nonequivalent aromatic prot
sets in the compound -
1(1) According to the 19C NMR, the number of nonequivalent carbons in the compou
1(g) According to your answer in Q 1(f) the compound has a plane of symmetry Yes a
NO =
1(h) The IUAC name for this unknown compound is =
Intensity-
Intensity
Transcribed Image Text:1. (Chapter 13 - Q57) The H and 1C NMR spectra of compound A, CaH9Br are sho below. Answer the following questions. Chem. Rel. shift area 1.20 3.00 2.58 2.00 2.00 2.00 707 7.39 TMS 10 O ppm 4 Chemical shift (8) TMS 200 180 160 140 120 100 Chemical shift (8) O ppm 20 1(a) Degree of the unsaturation of this compound is - 1(b) The derived unsaturation number indicates that compound has . a(c) Two peaks in between 6.5 - 8.0 0 indicate that compound is 1(d) According to the splitting pattern of the peak at 1.20 d and 2.58 ð indicates that compound has a. - group= 1(e) According to the H NMR spectrum the number of nonequivalent aromatic prot sets in the compound - 1(1) According to the 19C NMR, the number of nonequivalent carbons in the compou 1(g) According to your answer in Q 1(f) the compound has a plane of symmetry Yes a NO = 1(h) The IUAC name for this unknown compound is = Intensity- Intensity
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