100 80 60 40 20 % of base peak 4000 13C NMR Spectrum (50.0 MHz, CDCI, solution) proton decoupled 2 IR Spectrum (liquid film) el 40 200 L 4.0 43 73 3000 160 80 2 h M+ = 150/152 (<1%) I 120 160 200 m/e 1740 2000 120 1600 v (cm¹) 3.0 solvent 80 1200 40 Mass Spectrum C6H₁10₂ Cl 240 280 ри 800 0 3 O 8 (ppm) 2.0 22

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Helping identify the componets of each spevtrum and the whole compound/ name.

100
80
60
40
20
% of base peak
4000
13C NMR Spectrum
(50.0 MHz, CDCI, solution)
proton decoupled
2
IR Spectrum
(liquid film)
ek
40
200
4.0
43
73
3000
160
80
2
☐
dle
M+¹ = 150/152 (< 1%)
I
120 160
m/e
1740
2000
120
1600
V (cm¹)
3.0
solvent
80
200
1200
40
Mass Spectrum
C6H₁10₂ Cl
240 280
800
0
3
0
2.0
8 (ppm)
22
Transcribed Image Text:100 80 60 40 20 % of base peak 4000 13C NMR Spectrum (50.0 MHz, CDCI, solution) proton decoupled 2 IR Spectrum (liquid film) ek 40 200 4.0 43 73 3000 160 80 2 ☐ dle M+¹ = 150/152 (< 1%) I 120 160 m/e 1740 2000 120 1600 V (cm¹) 3.0 solvent 80 200 1200 40 Mass Spectrum C6H₁10₂ Cl 240 280 800 0 3 0 2.0 8 (ppm) 22
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