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-58 USE MESN ANALYSIS ↑ IS 12mA укл (is) TO Ri 2 КЛ FIND R₂ акл CURRENT R4 w 8x (12.) H→ 24V Vs SEPP

-58 USE MESN ANALYSIS ↑ IS 12mA укл (is) TO Ri 2 КЛ FIND R₂ акл CURRENT R4 w 8x (12.) H→ 24V Vs SEPP

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Did I solve this correctly? I am supposed to find I using MESH analysis for i1, i2, and i3.

58 USE MESN ANALYSIS ↑ Is 12mA Ra чкл is MESH ANALYSIS KVL @ i, : KVL @ is! TO Ri акл 3 RS FIND акл CURRENT R4 www ВКЛ (12²) I I→>> -10, +8ia +413 = 0 -) -41, +5ix - 23 = -12 × 10 -21, 2₂ +373 = 6x10-6 24v 2000 (1₁) + - (8000 (1₁-i₂)) + (4000 (i,- i₂)) = 0 2000 i, - 8000'i, + 800022 - 4000 i + 4000 i3 =0 -10 POOL, 8000 i +4000 l =0 -100, +8ia + 4iz = 0 2000 (iz-is) + 8000 (ia-i₁ ) + 24 =0 2009 i₁ - 2000 is + 80001 - 8000i, = -24 - 80001, +18000ia - 200013 = -24 KVL@iz: 4000 (i, - 1₁) + 2000 (is-in) = 12 x10-3 -10 -4 A reee - 4000 i, + 5000 in 1000 iz = -12 -4₁₁ + 51₂ - iz = -12x10-3 Vs 4000i, -4000i, + 20001 - 2000 1₂ = 12×10²³ -4000i, -2000 ia + 6000 iz = 12x10-3 -42₁-2ia +6iz = -12x10-6 -21₁ - 12 + 3i3 = 6x10-6 8 4 Ś -1 J A 3 I O -12×10-3 6x10-6 x = B FE
Transcribed Image Text:58 USE MESN ANALYSIS ↑ Is 12mA Ra чкл is MESH ANALYSIS KVL @ i, : KVL @ is! TO Ri акл 3 RS FIND акл CURRENT R4 www ВКЛ (12²) I I→>> -10, +8ia +413 = 0 -) -41, +5ix - 23 = -12 × 10 -21, 2₂ +373 = 6x10-6 24v 2000 (1₁) + - (8000 (1₁-i₂)) + (4000 (i,- i₂)) = 0 2000 i, - 8000'i, + 800022 - 4000 i + 4000 i3 =0 -10 POOL, 8000 i +4000 l =0 -100, +8ia + 4iz = 0 2000 (iz-is) + 8000 (ia-i₁ ) + 24 =0 2009 i₁ - 2000 is + 80001 - 8000i, = -24 - 80001, +18000ia - 200013 = -24 KVL@iz: 4000 (i, - 1₁) + 2000 (is-in) = 12 x10-3 -10 -4 A reee - 4000 i, + 5000 in 1000 iz = -12 -4₁₁ + 51₂ - iz = -12x10-3 Vs 4000i, -4000i, + 20001 - 2000 1₂ = 12×10²³ -4000i, -2000 ia + 6000 iz = 12x10-3 -42₁-2ia +6iz = -12x10-6 -21₁ - 12 + 3i3 = 6x10-6 8 4 Ś -1 J A 3 I O -12×10-3 6x10-6 x = B FE
(... CONTINUED) X = B. AV i₁ = $997 A, is = 9423 A, is = 11139 A 5x105 1x10² 1×106 I = 1₂ - i, I = (9423) - (11139) A I = -429 2.5X105
Transcribed Image Text:(... CONTINUED) X = B. AV i₁ = $997 A, is = 9423 A, is = 11139 A 5x105 1x10² 1×106 I = 1₂ - i, I = (9423) - (11139) A I = -429 2.5X105
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