1. CALCULATE ALL THE CURRENTS AND VOLTAGES FOR EACH RESISTOR USING EITHER KIRCHHOFF'S LAW OR MESH THEORY (SIMULTANEOUS EQUATIONS). ROK R4 330 R6 RK 1.0K 100V R0 R3 100 R5 R7 680

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Use mesh theory to solve for R1- R8 showing work for the voltages and current
### Electrical Circuit Analysis: Resistor Currents and Voltages

**Objective:**
Calculate all the currents and voltages for each resistor using either Kirchhoff's Law or Mesh Theory (simultaneous equations).

**Given Circuit:**

A circuit is shown with the following parameters:
- **Voltage Source**: 100V
- **Resistors**:
  - \( R1 = 1.0 \text{k}\Omega \)
  - \( R2 = 470 \Omega \)
  - \( R3 = 560 \Omega \)
  - \( R4 = 330 \Omega \)
  - \( R5 = 100 \Omega \)
  - \( R6 = 1.0 \text{k}\Omega \)
  - \( R7 = 680 \Omega \)
  - \( R8 = 1.5 \text{k}\Omega \)

**Diagram Explanation:**

1. The voltage source is on the left side of the diagram, providing a potential difference of 100V.
2. The circuit contains multiple resistors connected in series and parallel configurations.

**Connections:**
- From the positive terminal of the voltage source, the current flows through **R1 (1.0 kΩ)**.
- After **R1**, the current splits: 
  - One path goes through **R2 (470 Ω)** and then through **R3 (560 Ω)**, and then merges back.
  - The other path goes through **R4 (330 Ω)**.
- Post **R4**, it encounters **R6 (1.0 kΩ)** in series before reaching the parallel branch.
- At this point, one branch contains **R7 (680 Ω)** and the other contains **R8 (1.5 kΩ)**.
- These branches then come together and flow through **R5 (100 Ω)** back to the negative terminal of the voltage source.

**Assignment:**
We must calculate the currents and voltages across each resistor using:
1. **Kirchhoff's Current Law (KCL)**: At any junction in an electrical circuit, the sum of the currents entering the junction is equal to the sum of the currents leaving the junction.
2. **Kirchhoff's Voltage Law (KVL)**: The sum of the electrical potential differences (voltage) around any closed circuit loop is zero.
3. **Mesh Analysis**: This involves writing mesh equations for each independent loop
Transcribed Image Text:### Electrical Circuit Analysis: Resistor Currents and Voltages **Objective:** Calculate all the currents and voltages for each resistor using either Kirchhoff's Law or Mesh Theory (simultaneous equations). **Given Circuit:** A circuit is shown with the following parameters: - **Voltage Source**: 100V - **Resistors**: - \( R1 = 1.0 \text{k}\Omega \) - \( R2 = 470 \Omega \) - \( R3 = 560 \Omega \) - \( R4 = 330 \Omega \) - \( R5 = 100 \Omega \) - \( R6 = 1.0 \text{k}\Omega \) - \( R7 = 680 \Omega \) - \( R8 = 1.5 \text{k}\Omega \) **Diagram Explanation:** 1. The voltage source is on the left side of the diagram, providing a potential difference of 100V. 2. The circuit contains multiple resistors connected in series and parallel configurations. **Connections:** - From the positive terminal of the voltage source, the current flows through **R1 (1.0 kΩ)**. - After **R1**, the current splits: - One path goes through **R2 (470 Ω)** and then through **R3 (560 Ω)**, and then merges back. - The other path goes through **R4 (330 Ω)**. - Post **R4**, it encounters **R6 (1.0 kΩ)** in series before reaching the parallel branch. - At this point, one branch contains **R7 (680 Ω)** and the other contains **R8 (1.5 kΩ)**. - These branches then come together and flow through **R5 (100 Ω)** back to the negative terminal of the voltage source. **Assignment:** We must calculate the currents and voltages across each resistor using: 1. **Kirchhoff's Current Law (KCL)**: At any junction in an electrical circuit, the sum of the currents entering the junction is equal to the sum of the currents leaving the junction. 2. **Kirchhoff's Voltage Law (KVL)**: The sum of the electrical potential differences (voltage) around any closed circuit loop is zero. 3. **Mesh Analysis**: This involves writing mesh equations for each independent loop
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