Using mesh analysis, find Ohm's law equations for V1, V2, V3, V4, V5 The image displays an electrical circuit diagram featuring both voltage and current sources, as well as several resistors. Here is a detailed transcription and explanation of the components and their configuration:- **Voltage Sources**: - A 9V battery is connected across the top left part of the circuit. - A 12V battery is connected on the right side of the circuit.- **Current Sources**: - There is a current source providing 23A flowing downwards near the left side of the circuit, denoted as \( I_1 \). - Another current source provides 2A flowing upwards through the center-right of the circuit, denoted as \( I_4 \).- **Resistors**: - A 2Ω resistor is located on the left side of the circuit, with voltage \( V_1 \) across it. - A 5Ω resistor is situated toward the top center of the circuit with voltage \( V_2 \) across it. - A 6Ω resistor is connected toward the top right of the circuit with voltage \( V_5 \) across it. - A 3Ω resistor is located in the center of the circuit with voltage \( V_3 \) across it. - A 5Ω resistor is placed toward the bottom right of the circuit with voltage \( V_4 \) across it.- **Current Flows**: - Current \( I_2 \) flows through the 5Ω resistor (top center). - Current \( I_3 \) flows through the 3Ω resistor (center). - Current \( I_4 \) flows through the lower part of the circuit at 2A as noted earlier.The diagram provides a clear representation of the electrical circuit, allowing for analysis using Kirchhoff's laws or other circuit analysis techniques. Each component is clearly labeled with its respective resistance, current, and voltage. This setup is ideal for calculations involving series and parallel circuits, current and voltage division, and verification of these principles in an educational context.

Using ohm's law in mesh 1,there is just one current I1 generating voltage V1 .Hence V1=I1×2Ω Using ohm's law in mesh 2,there is just one current I2 generating voltage V2 .Hence V2=I2×5ΩUsing ohm's law in mesh 3,there are two currents I2 and I3.generating voltage V3 . However, looking at the polarity of V3 it follows the direction of I3. Hence, the resultant current will be I3-I2 V3=I3-I2×3Ω Using ohm's law in mesh 4, again there are two currents I3 and I4 generating voltage V4 . Polarity of V4 shows that it follows the direction of I4. Hence, the resultant current will be I4-I3 V4=I4-I3×5Ω Using ohm's law in mesh 4,there is one current I4 marked generating voltage V5 .Hence V5=I4×6Ω