Hi, I am trying to solve this circuit (see picture attached) but I am clearly doing something wrong. I am using KVL to find the voltage, so I was trying to find the currents I1, I2 and I3 first. Although, once I multiply the obtained equation (4) by 3 and subtract it from equation (3) I have zero as a result. What am I doing wrong? The goal would be to find the Voltage Vab.

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Hi, I am trying to solve this circuit (see picture attached) but I am clearly doing something wrong. I am using KVL to find the voltage, so I was trying to find the currents I1, I2 and I3 first. Although, once I multiply the obtained equation (4) by 3 and subtract it from equation (3) I have zero as a result. What am I doing wrong? The goal would be to find the Voltage Vab.

Tutorial
6
1 Calculate the voltage Vab in the circuit
22 C₂
24V
L
TH +
D
KVL (ECDE)
121₁ + 1₂ + 21 ₂₂
+21₂
3
ISA
1^
кис (с вос)
SI₂ + 1₂ = 21₂ = 1₂
Plug into
2 (-1₂-1₂) + 3 1₂
3)
+313
-24 = 0 =) 2 1₂ +5I₂ -24=
-21₂-21₂ +31₂3
-शू-श
+31₁₂-24 = 0
=O=)
Muevo y bas
THE
кас
Iz t Iz + Iz
(6) 12-1₂-13 0
2
61₂ - 313=0 (3
2
- 24 =0 =) -21₂ + 1₂ = 24 = d
t
1,
Transcribed Image Text:Tutorial 6 1 Calculate the voltage Vab in the circuit 22 C₂ 24V L TH + D KVL (ECDE) 121₁ + 1₂ + 21 ₂₂ +21₂ 3 ISA 1^ кис (с вос) SI₂ + 1₂ = 21₂ = 1₂ Plug into 2 (-1₂-1₂) + 3 1₂ 3) +313 -24 = 0 =) 2 1₂ +5I₂ -24= -21₂-21₂ +31₂3 -शू-श +31₁₂-24 = 0 =O=) Muevo y bas THE кас Iz t Iz + Iz (6) 12-1₂-13 0 2 61₂ - 313=0 (3 2 - 24 =0 =) -21₂ + 1₂ = 24 = d t 1,
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