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20 40° (St3-j4) I₁ -(3-j4) I₂ 10 490° (3-j4t2) I2-(3-j4) I, -213 -15 40°= -10 490° = (12+2) I3-212

20 40° (St3-j4) I₁ -(3-j4) I₂ 10 490° (3-j4t2) I2-(3-j4) I, -213 -15 40°= -10 490° = (12+2) I3-212

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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20 20° = (5t3-j4) I, - (3-j4) I2 10 4 90° = (3-j 4 +2) I 2- (3-j4) I₁ - 213 I, -15 40° = -10 490°= (12+2) I3-212
Transcribed Image Text:20 20° = (5t3-j4) I, - (3-j4) I2 10 4 90° = (3-j 4 +2) I 2- (3-j4) I₁ - 213 I, -15 40° = -10 490°= (12+2) I3-212
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