5:47 AM P on "D, 4G || all k60 LX Expert Help Maths Science 12:58 M 2.calculate the average time between collision of air assuming p=1atm and T=295K then m=28.8g/mol and the volume is 190cm³ using ideal gas law, determine the density of air under this condition Landon 2.calculate the average time between collision of air assuming p=1atm and T=295K then m=28.8g/mol and the volume is 190cm³ using ideal gas law, determine the density of air under this condition Given information P = 1 atm molar mass = 28.8 g T = 295 K mol V = 190 cm³ = 0.190 L Density PV = nRT 1 x V = 28.8 × 0.0821 × 295 28.8
5:47 AM P on "D, 4G || all k60 LX Expert Help Maths Science 12:58 M 2.calculate the average time between collision of air assuming p=1atm and T=295K then m=28.8g/mol and the volume is 190cm³ using ideal gas law, determine the density of air under this condition Landon 2.calculate the average time between collision of air assuming p=1atm and T=295K then m=28.8g/mol and the volume is 190cm³ using ideal gas law, determine the density of air under this condition Given information P = 1 atm molar mass = 28.8 g T = 295 K mol V = 190 cm³ = 0.190 L Density PV = nRT 1 x V = 28.8 × 0.0821 × 295 28.8
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:5:47 AM P
on "D, 4G || all k60 LX
Expert Help
Maths Science
12:58
M
2.calculate the average time between
collision of air assuming p=1atm and
T=295K then m=28.8g/mol and the volume
is 190cm³ using ideal gas law, determine
the density of air under this condition
Landon
2.calculate the average time between
collision of air assuming p=1atm and
T=295K then m=28.8g/mol and the volume
is 190cm³ using ideal gas law, determine
the density of air under this condition
Given information
P = 1 atm
molar mass = 28.8 g
T = 295 K
mol
V = 190 cm³ = 0.190 L
Density
PV = nRT
1 x V = 28.8 × 0.0821 × 295
28.8
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