5.28 Find a value zo of the standard normal random variable z such that NW a. P(zzo) = .0401 b. P(-zozzo) = .95 c. P(-zozzo) = .90 d. P(-zoz≤ zo) = .8740 e. P(-20 z≤ 0) = .2967 f. P(-2<< zo) = .9710 g. P(zzo) = .5 h P(z) = 0057
Q: Consider a normally distribr deviation of 10. Find P(90<
A: mean =85 standard deviation =10 to find P(90<X<100)
Q: A random variable x has a normal distribution with mean 1000 and standard deviation 100. Which of…
A: Given that a random variable X has a normal distribution with a mean of 1000 and a standard…
Q: If Z denotes the standard normal random variable , then P( -.58 < Z < .23) ?
A: The z-score is the number of standard deviations by which an event is occurring is over the mean…
Q: If z is a standard normal random variable, the area between z = -1.20 and z =0 is 0.3849, while the…
A: Z has standard normal distribution.
Q: Suppose z is a normal random variable. Find P ( Z > 1.84 ). Round your answer to four decimal…
A: Sketch the normal curve and shade the area to the right of z=1.84.
Q: Let x be a random variable representing the height of mature oak trees in a forest. A friend claims…
A: given data, claim:μ=100n=16x¯=106.3s=11.8df=n-1=16-1=15p-value =?
Q: P (Z < 1.69) = P (Z > -1.32) =
A:
Q: Because serum cholesterol is related to age and sex, some investigators prefer to express it in…
A: By using the Standard Normal distribution and to find probability we use standard normal table as…
Q: Let X be a normal random variable. If the mean and standard deviation of X are 45 and 5,…
A: Given, Let X be a normal random variable.mean of X(μ) = 45standard deviation of X(σ) = 5and X = 55
Q: For å distribution. The sample mean =14.5, sample variance =25, to.05.15=1.753. Then the upper bound…
A: From the given information we find the upper bound .
Q: 4P2] Let Z be a standard normal variable. Find the following probabilities: 3. P (Z > 2.15) = 4. P…
A:
Q: Find a value of the standard normal random variable z, call a. P(zszo)=0.0283 b. P(-Zo szsz0)= 0.90…
A: Givena)P(z≤z0)=0.0283
Q: Given the standard normal random variable Z, find Pr(-2.08 <ZS 1.76). O A. 0.9420 O B. 0.0580 O C.…
A: We need to compute Pr(−2.08≤Z≤1.76), where Z has a standard normal distribution.
Q: The standard deviation of a normally distributed X random variable is 1.75. The probability that X…
A: As given, The standard deviation of X is 1.75. That is, σ = 1.75 The probability that X is between…
Q: Suppose x is a normally distributed random variable with mean μ=88.09 and standard deviation…
A: Given that, mean μ=88.09 and standard deviation σ=21.31 P(x<55.65)=? P(x>138.14)=?…
Q: = A population of values has a normal distribution with u to draw a random sample of size n = 179.…
A: Given: X ~ N(μ,σ) Where, μ = 245.3, and σ = 80.6. The sample size n=179.
Q: Suppose that Z is a normal random variable. Fine P(Z>1.91).
A: Solution:- from given information Suppose that Z is a normal random variable
Q: Let X be a discrete random variable with Poisson distribution, and with a standard deviation of 6.5.…
A:
Q: Find the following probability for the standard normal random variable z. e. P(z>0) f.…
A: Since the question has multiple subparts, as per the Bartleby policy, I will only solve first three…
Q: Suppose a random variable x follow a normal distribution of N[0,( 1 3 ) 2 ]. Let z = 9x 2 , what is…
A: It is given that, x follows a normal distribution of N[0, (1/3)2].
Q: Z is a standard normal random variable. Use Excel to find Pr(Z < -1.31). Enter your answer as a…
A: given data standard normal distributionZ~N(0,1)P(z<-1.31)=?
Q: A continuous random variable X is normally distributed with a mean of 56.3 and standard deviation of…
A:
Q: Let X be a normal random variable with mean 142 and standard deviation 6.35. What is P(X >= 128)? O…
A: Answer: From the given data, X is a normal random variable with Mean (μ) = 142 Standard deviation…
Q: If X represents a random variable coming from a normal distribution and P(X 6.5) = 0.59. True O…
A: It is given that P(X<6.5)=0.41.
Q: Suppose the random variable Z follows a standard normal distribution. Then the probability is 0.67…
A: Given that,The random variable Z follows a standard normal distribution.
Q: Let Z be a standard normal variable. Find the following probabilities: P (Z - 0.23)
A:
Q: Use Appendix Table III to determine to 5 decimal places the following probabilities for the standard…
A:
Q: X is a normal random variable with mean 5.0 and standard deviation 1.25. Find P (X> 6.26). (Round to…
A: Given mean is 5.0 and standard deviation is 1.25.
Q: Let x be a random variable representing the dividend yield of some stocks. Assume x has a normal…
A: State the hypotheses.
Q: 4.64 Let y be a random variable having a normal distribution with a mean equal to 50 and a standard…
A: According to the given information in this question We need to find the following probability
Q: Let Z denote the standard normal random variable, ?(−.54<?≤.78)is closest to
A:
Q: Q3: Let i be the observed mean of a random sample of size n from a distribution having mean u and…
A: Hello! As you have posted 2 different questions, we are answering the first question. In case you…
Q: For a normally distributed random variable with mean is 46 and standard deviation is 18, Find the Z…
A: Answer: From the given data, mean (μ) = 46 Standard deviation(σ) = 18
Q: A random variable X is assumed to be normally distributed with a mean of 200 and a standard…
A:
Q: [4P1] Let Z be a standard normal variable. Find the following probabilities: P (Z -1.23) =
A: Find probability for given data by using z score table..
Q: [5P2A] Let Z be a standard normal variable. Find the following probabilities: 3. P (Z > 2.05) = 4.…
A: We have to find given probability..
Q: Find the following probability for the standard normal random variable z. e. P(z20) f. P(-2.54 sz…
A:
Q: 4. Let Z be the standardized normal variable, i.e. Z follows normal distribution with the mean μ =…
A: Solution: a). P(Z < -0.6) = 0.27425 {From standard normal table} The shaded area…
Step by step
Solved in 2 steps with 13 images
- Use the Suppose in a local Kindergarten through 12th grade (K -12) school district, 42% of the population favor a charter school for grades K through 5. A simple random sample of 144 is surveyed. nd the mean and the standard deviation of X of B(144, 0.42). Round off to 4 decimal places. b. Now approximate X of B(144, 0.42) using the normal approximation with the random variable Y and the table. Round off to 4 decimal places. Y N( C Find the probability that at most 72 favor a charter school using the normal approximation and the table. Round off to z-values up to 2 decimal places.) P(X 68) P(Y > ~ (Z >) e. Find the probability that exactly 63 favor a charter school using the normal approximation and the table. (Round off to z-values up to 2 decimal places.) P(X = 63) P(a) Find such that P( X < ? ) = 0.9332, where X is a normal random variable with mean = 10 and standard deviation = 2.5. b) Find such that P( X > ?) = 0.1230, where X is a normal random variable with mean = 10 and standard deviation = 2.5.Assume the random variable X is normally distributed, with mean u= 57 and standard deviation o = 7, Find the 12th percentile. The 12th percentile is (Round to two decimal places as needed.)
- Suppose that X is a normal random variable with a mean of μ=10. If we know that Pr[X<46]=Pr[Z<3.00], where Z is the standard normal random variable, determine the standard deviation of X.Q1A Hi wonderful Bartleby team, I need help with this exercise, please provide answer and short explanation for all the answers. Thanks in advance. The last part of it is the sentence and the options are: -(Reject/ Fail to reject) the null hypothesis. There (Is / Not) sufficient evidence to support the claim that those treated with magnets have a greater mean reduction in pain than those given a sham treatment.X is a normally distributed random variable with a mean of 5.00 and a standard deviation of 11.39. If the right area is 0.4716 then what is the value of X?
- For a Normal Random Variable X with a mean of 80 and a Standard Deviation of 7, find P(80Suppose the random variable X follows a binomial distribution with n = 0.50. Using the normal approximation, what is the value for P(X > 38)? 100 and p =Jarþrúður, a geologist is working with the random variable Z that follows the standard normal distribution. What is the value of z if P (Z> z) = 0.0968?Recommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
Probability and Statistics for Engineering and th…StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage Learning
Statistics for The Behavioral Sciences (MindTap C…StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. WallnauPublisher:Cengage Learning
Elementary Statistics: Picturing the World (7th E…StatisticsISBN:9780134683416Author:Ron Larson, Betsy FarberPublisher:PEARSON
The Basic Practice of StatisticsStatisticsISBN:9781319042578Author:David S. Moore, William I. Notz, Michael A. FlignerPublisher:W. H. Freeman
Introduction to the Practice of StatisticsStatisticsISBN:9781319013387Author:David S. Moore, George P. McCabe, Bruce A. CraigPublisher:W. H. FreemanMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th…StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C…StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. WallnauPublisher:Cengage LearningElementary Statistics: Picturing the World (7th E…StatisticsISBN:9780134683416Author:Ron Larson, Betsy FarberPublisher:PEARSONThe Basic Practice of StatisticsStatisticsISBN:9781319042578Author:David S. Moore, William I. Notz, Michael A. FlignerPublisher:W. H. FreemanIntroduction to the Practice of StatisticsStatisticsISBN:9781319013387Author:David S. Moore, George P. McCabe, Bruce A. CraigPublisher:W. H. Freeman