A population of values has a normal distribution with \( \mu = 245.3 \) and \( \sigma = 80.6 \). You intend to draw a random sample of size \( n = 179 \).**Find the probability that a single randomly selected value is between 227.2 and 241.1.**\[ P(227.2 < X < 241.1) = \] [Enter your answer here]**Find the probability that a sample of size \( n = 179 \) is randomly selected with a mean between 227.2 and 241.1.**\[ P(227.2 < M < 241.1) = \] [Enter your answer here]Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.

Answered: = A population of values has a normal…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The percent of fat calories that a person consumes each day is normally distributed with a mean of about 35 and a standard deviation of about ten. Suppose that 9 individuals are randomly chosen. Let X = average percent of fat calories. For the group of 9, find the probability that the average percent of fat calories consumed is more than six. (Round your answer to four decimal places.)
Dandelions have effects on crop production and lawn growth and are studied. In one region, the mean number of dandelions per square meter was found to be 10.8.Find the probability of no dandelions in an area of 1 m².P(X=0)=P(X=0)= Find the probability of at least one dandelion in an area of 1 m².P(at least one) = Find the probability of at most two dandelions in an area of 1 m².P(X≤2)=P(X≤2)=
A researcher recorded the number of shots made, X, out of 10 free throws by a sample of 1000 randomly selected college students. The table below is a probability distribution table representing the data collected. Calculate the mean and the standard deviation of the probability distribution using a TI-83, TI-83 Plus, or TI-84 graphing calculator. x P(x) 0 0.01 1 0.01 2 0.02 3 0.04 4 0.03 5 0.05 6 0.21 7 0.29 8 0.21 9 0.08 10 0.05
Let XX represent the full height of a certain species of tree. Assume that XX has a normal probability distribution with a mean of 320 ft and a standard deviation of 45 ft.Find the probability that the height of a randomly selected tree is between 334 ft and 388 ft. P(334 < X < 388) = Enter your answer as a number accurate to 3 decimal places.
1. Let XX represent the full height of a certain species of tree. Assume that XX has a normal probability distribution with a mean of 231.1 ft and a standard deviation of 5.6 ft.A tree of this type grows in my backyard, and it stands 230 feet tall. Find the probability that the height of a randomly selected tree is as tall as mine or shorter.P(X<230) = Enter your answer accurate to 4 decimal places. 2. Assume that z-scores are normally distributed with a mean of 0 and a standard deviation of 1.If P(−0.7<z<b)=0.7352P find b.b= (Round to two decimal places.) Do not round until the very last step. Any intermediate steps should include all decimal places.
= Assume that the probability of a being born with Genetic Condition B is p sample of 291 volunteers. 29/30. A study looks at a random Find the most likely number of the 291 volunteers to have Genetic Condition B. (Round answer to one decimal place.) P = Let X represent the number of volunteers (out of 291) who have Genetic Condition B. Find the standard deviation for the probability distribution of X. (Round answer to two decimal places.) O= Use the range rule of thumb to find the minimum usual value µ-20 and the maximum usual value μ+2o. Enter answer as an interval using square-brackets only with whole numbers. usual values =
The percent of fat calories that a person in America consumes each day is normally distributed with a mean of about 36 and a standard deviation of 10. Suppose that one individual is randomly chosen. Let X=percent of fat calories. Round all answers to 4 decimal places if where possible a. What is the distribution of X? X N( b. Find the probability that a randomly selected fat calorie percent is more than 40. c. Find the minimum number for the lower quarter of percent of fat calories.
average number of pounds of meat that a person consumes per year is 218pounds. Assume that the standard deviation is 26 pounds and the distribution is approximately normal. 1- Find the probability that a person selected at random consumes less than 224 pounds per year 2-1f a sample of 50 individuals is selected find the probability that the mean of the sample will be less than 224 pounds per year
Assuming a population is normally distributed, calculate the probability that a random member of the population falls between 3 standard deviations below the mean and 1 standard deviation below the mean. In other words in mathematical notation: P(-3 < z < -1) Enter your answer in decimal form. For example, 75% should be entered as 0.75.
Suppose that the weight of an newborn fawn is Uniformly distributed between 2.2 and 3 kg. Suppose that a newborn fawn is randomly selected. Round answers to 4 decimal places when possible. a. The mean of this distribution is b. The standard deviation is c. The probability that fawn will weigh exactly 2.8 kg is P(x = 2.8) = d. The probability that a newborn fawn will be weigh between 2.6 and 2.8 is P(2.6 < x < 2.8) =
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Assume that IQ scores are normally distributed, with a mean of 100 points and a standard deviation of 14 points. If 50 people are chosen at random, what is the probability that the sample mean of IQ scores will be between 98 and 102?P(98 ≤ x ≤ 102) = ?

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