Let XX represent the full height of a certain species of tree. Assume that XX has a normal probability distribution with a mean of 161 ft and a standard deviation of 7.1 ft. A tree of this type grows in my backyard, and it stands 145.4 feet tall. Find the probability that the height of a randomly selected tree is as tall as mine or shorter. P(X<145.4)P(X<145.4) = My neighbor also has a tree of this type growing in her backyard, but hers stands 150.4 feet tall. Find the probability that the full height of a randomly selected tree is at least as tall as hers. P(X>150.4)P(X>150.4) = Enter your answers as decimals accurate to 3 decimal places.
Let XX represent the full height of a certain species of tree. Assume that XX has a
A tree of this type grows in my backyard, and it stands 145.4 feet tall. Find the probability that the height of a randomly selected tree is as tall as mine or shorter.
P(X<145.4)P(X<145.4) =
My neighbor also has a tree of this type growing in her backyard, but hers stands 150.4 feet tall. Find the probability that the full height of a randomly selected tree is at least as tall as hers.
P(X>150.4)P(X>150.4) =
Enter your answers as decimals accurate to 3 decimal places.
Solution:
Let X be the full height of certain species of tree has a normal distribution with mean 161 ft and standard deviation 7.1 ft.
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