Let \( X \) represent the full height of a certain species of tree. Assume that \( X \) has a normal probability distribution with a mean of 160.5 ft and a standard deviation of 9.7 ft.A tree of this type grows in my backyard, and it stands 162.4 feet tall. Find the probability that the height of a randomly selected tree is as tall as mine or shorter.\[ P(X < 162.4) = \]My neighbor also has a tree of this type growing in her backyard, but hers stands 169.2 feet tall. Find the probability that the full height of a randomly selected tree is at least as tall as hers.\[ P(X > 169.2) = \]Enter your answers as decimals accurate to 4 decimal places.

Answered: Image /qna-images/answer/c08cb887-54e8-4910-88e3-d4a887a79a2b.jpg

Answered: Let X represent the full height of a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose that a brand of lightbulb lasts on average 1690 hours with a standard deviation of 194 hours. Assume the life of the lightbulb is normally distributed. Calculate the probability that a particular bulb will last from 1418 to 2183 hours?
Assume that adults have IQ scores that are normally distributed with a mean of µ = 100 and a standard deviation o = 20. Find the probability that a randomly selected adult has an IQ between 80 and 120.
Let XX represent the full height of a certain species of tree. Assume that XX has a normal probability distribution with a mean of 97.9 ft and a standard deviation of 5.4 ft.A tree of this type grows in my backyard, and it stands 86 feet tall. Find the probability that the height of a randomly selected tree is as tall as mine or shorter.P(X<86)P(X<86) = My neighbor also has a tree of this type growing in her backyard, but hers stands 112.5 feet tall. Find the probability that the full height of a randomly selected tree is at least as tall as hers.P(X>112.5)P(X>112.5) = Enter your answers as decimals accurate to 4 decimal places.
An elevator has a placard stating that the maximum capacity is 4400 lb-29 passengers. So, 29 adult male passengers can have a mean weight of up to 4400/29 = 152 pounds. Assume that weights of males are normally distributed with a mean of 180 lb and a standard deviation of 29 lb. a. Find the probability that 1 randomly selected adult male has a weight greater than 152 lb. b. Find the probability that a sample of 29 randomly selected adult males has a mean weight greater than 152 lb. c. What do you conclude about the safety of this elevator? a. The probability that 1 randomly selected adult male has a weight greater than 152 lb is ☐ (Round to four decimal places as needed.)
Dandelions have effects on crop production and lawn growth and are studied. In one region, the mean number of dandelions per square meter was found to be 10.8.Find the probability of no dandelions in an area of 1 m².P(X=0)=P(X=0)= Find the probability of at least one dandelion in an area of 1 m².P(at least one) = Find the probability of at most two dandelions in an area of 1 m².P(X≤2)=P(X≤2)=
A randomly selected group of 560 students are assumed to have heights distributed normally with meanµ = 166 cm and standard deviation σ = 30 cm. Suppose a student is chosen randomly from this group. Finda. the probability that this student’s height is between 170 cm and 182 cm.b. the probability that this student’s height is bigger than 175 cm.
Let XX represent the full height of a certain species of tree. Assume that XX has a normal probability distribution with a mean of 320 ft and a standard deviation of 45 ft.Find the probability that the height of a randomly selected tree is between 334 ft and 388 ft. P(334 < X < 388) = Enter your answer as a number accurate to 3 decimal places.
Let X represent the full height of a certain species of tree. Assume that X has a normal probability distribution with a mean of 58.2 ft and a standard deviation of 4.8 ft. A tree of this type grows in my backyard, and it stands 56.8 feet tall. Find the probability that the height of a randomly selected tree is as tall as mine or shorter. P(X<56.8)= My neighbor also has a tree of this type growing in her backyard, but hers stands 61.1 feet tall. Find the probability that the full height of a randomly selected tree is at least as tall as hers. P(X>61.1)= Enter your answers as decimals accurate to 4 decimal places.
1. Let XX represent the full height of a certain species of tree. Assume that XX has a normal probability distribution with a mean of 231.1 ft and a standard deviation of 5.6 ft.A tree of this type grows in my backyard, and it stands 230 feet tall. Find the probability that the height of a randomly selected tree is as tall as mine or shorter.P(X<230) = Enter your answer accurate to 4 decimal places. 2. Assume that z-scores are normally distributed with a mean of 0 and a standard deviation of 1.If P(−0.7<z<b)=0.7352P find b.b= (Round to two decimal places.) Do not round until the very last step. Any intermediate steps should include all decimal places.
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find the probability of obtaining a reading greater than -0.71°C.
The scores in a large Algebra class are normally distributed with a mean of 65 and a standard deviation of 11. If a random sample of 25 students is selected, find the probability that the sample mean will be between 63 and 70.
The length of the western rattlesnake is normally distributed with a mean of 42 inches and a standard deviation of 2.04 inches. Let X be the length of one of these snakes selected at random. Determine the probability that the snake is longer than 45 inches. Report your answer to four decimal places (like .1567).

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