Suppose that the weight of an newborn fawn is Uniformly distributed between 1.6 and 3.2 kg. Suppose that a newborn fawn is randomly selected. Round answers to 4 decimal places when possible. c. The probability that fawn will d. The probability that a newborn fawn will be weigh between 1.7 a. The mean of this distribution is b. The standard deviation is weigh exactly 2.7 kg is P(x = 2.7) =
Suppose that the weight of an newborn fawn is Uniformly distributed between 1.6 and 3.2 kg. Suppose that a newborn fawn is randomly selected. Round answers to 4 decimal places when possible. c. The probability that fawn will d. The probability that a newborn fawn will be weigh between 1.7 a. The mean of this distribution is b. The standard deviation is weigh exactly 2.7 kg is P(x = 2.7) =
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![Suppose that the weight of an newborn fawn is Uniformly distributed between 1.6 and 3.2 kg. Suppose that a
newborn fawn is randomly selected. Round answers to 4 decimal places when possible.
a. The mean of this distribution is
b. The standard deviation is
c. The probability that fawn will
weigh exactly 2.7 kg is P(x = 2.7) =
d. The probability that a newborn fawn will be weigh between 1.7
and 2.2 is P(1.7 <x<2.2) =
e. The probability that a newborn fawn will be weigh more than 2.02 is P(x
> 2.02) =
f. P(x > 2.2 | x< 2.8) =
g. Find the 48th percentile.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F34d9745c-6a6d-40f6-8714-a70c9089854c%2F759cd161-ae16-449e-affb-09bebde7f771%2Fpna0vdf_processed.png&w=3840&q=75)
Transcribed Image Text:Suppose that the weight of an newborn fawn is Uniformly distributed between 1.6 and 3.2 kg. Suppose that a
newborn fawn is randomly selected. Round answers to 4 decimal places when possible.
a. The mean of this distribution is
b. The standard deviation is
c. The probability that fawn will
weigh exactly 2.7 kg is P(x = 2.7) =
d. The probability that a newborn fawn will be weigh between 1.7
and 2.2 is P(1.7 <x<2.2) =
e. The probability that a newborn fawn will be weigh more than 2.02 is P(x
> 2.02) =
f. P(x > 2.2 | x< 2.8) =
g. Find the 48th percentile.
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