Assume the random variable X is normally distributed with mean μ =50 and standard deviation o=7. Find the 96th percentile Click the icon to view a table of areas under the normal curve The 96th percentile is (Round to two decimal places as needed.) www M
Assume the random variable X is normally distributed with mean μ =50 and standard deviation o=7. Find the 96th percentile Click the icon to view a table of areas under the normal curve The 96th percentile is (Round to two decimal places as needed.) www M
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question

Transcribed Image Text:Tables of Areas under the Normal Curve
Arca
z
TABLE V
-3.4
-3.3
-3.2
-3.1
-3.0
.00
-2.4
-2.3
-2.2
.03
Wald
0.0003 0.0003 0.0003 0.0003 0.0003
0.0005 0.0005 0.0005 0.0004 0.0004
0.0007 0.0007 0.0006 0.0006 0.0006
0.0010
0.0009
0.0009 0.0009
0.0008
0.0013 0.0013 0.0012 0.0012
0.0013
ngay
bildigal menjad
<-29 0.0019 0.0018 0.0018 0.0017 0.0016
-2.8 0.0026
0.0024 0.0023 0.0023 0.0022
0.0025
-2.7 0.0035
0.0031 0.0030
0.0034 0.0033 0.0032
0.0040
<-26 0.0047 0.0045 0.0044 0.0043 0.0041
-25
0.0062 0.0060 0.0059 0.0057 -0.0055 0.0054
0.0073 -0.0071
0.0096 0.0094
0.0125
0.0122
0.0082
0.0107
0.0139
.01
0.0179
0.0228
0.0080
0.0104
0.0136
0.0174
0,0222
Standard Normal Distribution
.04
.05 .06
.02
Print
0.0078
0.0102
0.0132
0.0075
0.0099
0.0129
.07
.08
.09
0.0003 0.0003 0.0003 0.0003 0.0002
0.0004 0.0004 0.0004 0.0003
0.0004
0.0006 0.0006 0.0005 0.0005 0.0005
0.0008
0.0008 0.0008
0.0007 0.0007
0.0011 0.0011 0.0011 0.0010 0.0010
Done
0.0016 0.0015
0.0021
0.0029
0.0039
0.0052
0.0170
0.0166
0.0162
-2.0
the pre
0.0207
0.0217 0.0212
To combily's wel zyour
0.0262 0.0256 0.0250 0.0244 0.0239 0.0233
-1.9 0.0287 0.0281 0.0274 0,0268
0.0314 0.0307 0.0301 0.0294
-1.8 0.0359 0.0351 0.0344 0.0336 0.0329 0.0322
0.0384 0.0375 0.0367
-1.7 0.0446 0.0436 0.0427 0.0418 0.0409 0.0401 0.0392
0.0485 0.0475 0.0465 0.0455
-L6 0.0548 0.0537 0.0526 0.0516 0.0505 0.0495
0.0594 0.0582 0.0571 0.0559
-1.5 0.0668 0.0655 0.0643 0.0630 0.0618 0.0606
0.0735 0.0721 0.0708 0.0694 0.0681
-1.4 0.0808 0.0793 0.0778 0.0764 0.0749
0.0853 0.0838 0.0823
-1.3 0.0968 0.0951 0.0934 0.0918 0.0901 0.0885 0.0869
0.1003 0.0985
-1.2 0.1151 0.1131 0.1112 0.1093 0.1075 0.1056 0.1038 0.1020
-1.1
0.1357 0.1335 0.1314 0.1292 0.1271 0.1251 0.1230 0.1210 0.1190 0.1170
-1.0 0.1587 0.1562 0.1539 0.1515 0.1492 0.1469 0.1446 0.1423 0.1401 0.1379
-0.9
0.1841 0.1814 0.1788 0.1762 0.1736 0.1711 0.1685 0.1660 0.1635 0.1611
-0.8 0.2119 0.2090 0.2061 02033 0.2005 0.1977 0.1949 0.1922 0.1895 0.1867
-0.7 0.2420 0.2389 0.2358 02327 0.2296 0.2266 0.2236 0.2206 02177 0,2148
02743
-0.6
0.2676 02613 07611 02578 02546 02514 02483 02451
200
0.0015 0.0014 0.0014
0.0021 0.0020 0.0019
0.0028 0.0027 0.0026
0.0038 0.0037 0.0036
0.0051 0.0049 0.0048
0.0069 0.0068 0.0066 0.0064
0.0091 0.0089 0.0087 0.0084
0.0119 0.0116 0.0113 0.0110
0.0146 0.0143
0.0154 0.0150
0.0158
0.0202 0.0197 0.0192 0.0188 0.0183
- X

Transcribed Image Text:Assume the random variable X is normally distributed with mean = 50 and standard deviation o=7. Find the 96th percentile.
Click the icon to view a table of areas under the normal curve
The 96th percentile is
(Round to two decimal places as needed.)
ww.
W
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