Suppose that the weight of an newborn fawn is Uniformly distributed between 2.3 and 3.6 kg. Suppose that a ewborn fawn is randomly selected. Round answers to 4 decimal places when possible. . The mean of this distribution is b. The standard deviation is c. The probability that fawn will veigh exactly 2.8 kg is P(x = 2.8) = d. The probability that a newborn fawn will be weigh between 2.4 nd 2.7 is P(2.4 2.8 | x<3.2) = g. Find the 84th percentile. %3D

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Suppose that the weight of an newborn fawn is Uniformly distributed between 2.3 and 3.6 kg. Suppose that a
newborn fawn is randomly selected. Round answers to 4 decimal places when possible.
a. The mean of this distribution is
b. The standard deviation is
c. The probability that fawn will
weigh exactly 2.8 kg is P(x = 2.8) =
d. The probability that a newborn fawn will be weigh between 2.4
%3|
and 2.7 is P(2.4 <x<2.7) =
e. The probability that a newborn fawn will be weigh more than 3.16 is P(x
> 3.16) =
f. P(x > 2.8 | x< 3.2) =
g. Find the 84th percentile.
Transcribed Image Text:Suppose that the weight of an newborn fawn is Uniformly distributed between 2.3 and 3.6 kg. Suppose that a newborn fawn is randomly selected. Round answers to 4 decimal places when possible. a. The mean of this distribution is b. The standard deviation is c. The probability that fawn will weigh exactly 2.8 kg is P(x = 2.8) = d. The probability that a newborn fawn will be weigh between 2.4 %3| and 2.7 is P(2.4 <x<2.7) = e. The probability that a newborn fawn will be weigh more than 3.16 is P(x > 3.16) = f. P(x > 2.8 | x< 3.2) = g. Find the 84th percentile.
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