Use Appendix Table III to determine to 5 decimal places the following probabilities for the standard normal random variable Z: (a) P(Z < 1.32) = i (b) P(Z < 2.7) = i (c) P(Z > 1.45) = i (d) P(Z > 2.15) = i (e) P(-2.34 < Z < 1.76) = i
Q: bie XIDUa to dětérminė to 5 décimal places the following proba (a) P(Z 1.45) = (d) P(7
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Q: Let Z be a standard normal random variable. Calculate the following probabilities using the ALEKS…
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Q: (a) P(Z 1.72) = 0 %3D (c) P(-0.67 < z < 2.20) = D %3D
A: Reviewing information, Z : Standard normal random variable
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- Let Z be a standard normal random variable. Calculate the following probabilities using the ALEKS calculator. Round your responses to at least three decimal places. (a) P(Z > -1.85) = 0 (b) P(Z s -1.99) = [] (c) P (0.80 < z < 1.91) = |Find the following probabilities for the standard normal random variable z (Keep in mind that the mean of the standard normal distribution is 0 and its standard deviation is 1). 1. P(z -1.42) = (Round your answer to 4 decimal places)Let Z be a standard normal random variable. Calculate the following probabilities. Round your response to at least three decimal places.
- Let z denote a random variable that has a standard normal distribution. Determine each of the probabilities below. (Round your answers to four decimal places.) In USE SALT (a) P(z < 2.37) : (b) P(z < 2.37) (c) P(z < -1.22) = (d) P(1.15 < z < 3.36) = You may need to use the appropriate table in the appendix to answer this question.How were the answers of 0.0344, 0.4656, 0.1470, and 0.1470 attained?Let z denote a random variable that has a standard normal distribution. Determine each of the probabilities below. (Round all answers to four decimal places.) (a) P(z 2) (g) P(z z -3.38) %3D (h) P(z < 4.98) %3D
- Supposed Y follow a binomial distribution with n = 15 and p = 0.4. a.) Find the exact probabilities of Y < 8 and Y = 8 (from the included tables). b.) Compare these to the corresponding values found by using the normal approximation (from the included tables).If Z is a standard normal random variable, find the value z, for the following probabilities. (Round your answers to two decimal places.) (a) P(Z > z,) = 0.5 (b) P(Z < z) = 0.8907 (c) P(-z,Let z be a standard normal random variable with mean ? = 0 and standard deviation ? = 1. Use Table 3 in Appendix I to find the probability. (Round your answer to four decimal places.) To the left of 1.3Tutorial Exercise Given that z is a standard normal random variable, compute the following probabilities. (a) P(-1.95 sz s 0.46) (b) P(0.55 sz s 1.23) (c) P(-1.85 ≤zs -1.05) Step 1 (a) P(-1.95 sz≤ 0.46) For z to be a standard normal variable means that the random variable z follows a normal distribution with mean 0 and standard deviation 1. The normal distribution is a bell-shaped curve that is symmetric about the mean. The graph of a standard normal curve is below. -3 -2 -1 0 mean, " z -2.0 -1.9 1 This distribution is continuous, so probabilities will be for a range of values and represented by the area under the graph between the values. The desired probability is for the region between z = -1.95 and z = 0.46. Since z = -1.95 is to the left of z = 0.46, we can find this probability by subtracting the area under the curve to the left of z = -1.95 2 3 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.0228 0.0222 0.0217 0.0212 0.0207 0.0202 0.0197 0.0192 0.0188 0.0183 0.0287 0.0281…Let Z be a standard normal random variable. Calculate the following probabilities and round your response to at least 3 decimal places. P(Z is less than or equal to -2.12)= P(Z>-0.71)= P(0.92<Z<2.09)=Given that z is a standard normal random variable, compute the following probabilities (to 4 decimals). a. P(-1.98 < z< 0.49) b. P(0.58SEE MORE QUESTIONSRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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