Let z be a standard normal random variable with mean ? = 0 and standard deviation ? = 1. Use Table 3 in Appendix I to find the probability. (Round your answer to four decimal places.) To the left of 1.3 ■Table 3 Areas under the Normal CurveZ-3.4-3.3-3.2-3.1-3.0-2.9-2.8-2.7-2.6-2.5-2.4-2.3-2.2-2.1-2.0-1.9-1.8-1.7-1.6-1.5-1.4-1.3-1.2-1.1-1.0-0.9-0.8-0.7-0.6-0.5-0.4-0.3-0.2-0.1-0.0.00.0003.0005.0007.0010.0013.0019.0026.0035.0047.0062.0082.0107.0139.0179.0228.0287.0359.0446.0548.0668.0808.0968.1151.1357.1587.1841.2119.2420.2743.3085.3446.3821.4207.4602.5000.01.0003.0005.0007.0009.0013.0018.0025.0034.0045.0060.0080.0104.0136.0174.0222.0281.0351.0436.0537.0655.0793.0951.1131.1335.1562.1814.2090.2389.2709.3050.3409.3783.4168.4562.4960.02.0003.0005.0006.0009.0013.0017.0024.0033.0044.0059.0078.0102.0132.0170.0217.0274.0344.0427.0526.0643.0778.0934.1112.1314.1539.1788.2061.2358.2676.3015.3372.3745.4129.4522.4920.03.0003.0004.0006.0009.0012.0017.0023.0032.0043.0057.0075.0099.0129.0166.0212.0268.0336.0418.0516.0630.0764.0918.1093.1292.1515.1762.2033.2327.2643.2981.3336.3707.4090.4483.4880.04.0003.0004.0006.0008.0012.0016.0023.0031.0041.0055.0073.0096.0125.0162.0207.0262.0329.0409.0505.0618.0749.0901.1075.1271.1492.1736.2005.2296.2611.2946.3300.3669.4052.4443.4840.05.0003.0004.0006.0008.0011.0016.0022.0030.0040.0054.0071.0094.0122.0158.0202.0256.0322.0401.0495.0606.0735.0885.1056.1251.1469.1711.1977.2266.2578.2912.3264.3632.4013.4404.4801.06.0003.0004.0006.0008.0011.0015.0021.0029.0039.0052.0069.0091.0119.0154.0197.0250.0314.0392.0485.0594.0722.0869.1038.1230.1446.1685.1949.2236.2546.2877.3228.3594.3974.4364.4761.07.0003.0004.0005.0008.0011.0015.0021.0028.0038.0051.0068.0089.0116.0150.0192.0244.0307.0384.0475.0582.0708.0853.1020.1210.1423.1660.1922.2206.2514.2843.3192.3557.3936.4325.4721.08.0003.0004.0005.0007.0010.0014.0020.0027.0037.0049.0066.0087.0113.0146.0188.0239.0301.0375.0465.0571.0694.0838.1003.1190.1401.1635.1894.2177.2483.2810.3156.3520.3897.4286.4681.09.0002.0003.0005.0007.0010.0014.0019.0026.0036.0048.0064.0084.0110.0143.0183.0233.0294.0367.0455.0559.0681.0823.0985.1170.1379.1611.1867.2148.2451.2776.3121.3483.3859.4247.4641 Table 3 (continued)Z0.00.10.20.30.40.50.60.70.80.91.01.11.21.31.41.51.61.71.81.92.02.12.22.32.42.52.62.72.82.93.03.13.23.33.4.00.5000.5398.5793.6179.6554.6915.7257.7580.7881.8159.8413.8643.8849.9032.9192.9332.9452.9554.9641.9713.9772.9821.9861.9893.9918.9938.9953.9965.9974.9981.9987.9990.9993.9995.9997.01.5040.5438.5832.6217.6591.6950.7291.7611.7910.8186.8438.8665.8869.9049.9207.9345.9463.9564.9649.9719.9778.9826.9864.9896.9920.9940.9955.9966.9975.9982.9987.9991.9993.9995.9997.02.5080.5478.5871.6255.6628.6985.7324.7642.7939.8212.8461.8686.8888.9066.9222.9357.9474.9573.9656.9726.9783.9830.9868.9898.9922.9941.9956.9967.9976.9982.9987.9991.9994.9995.9997.03.5120.5517.5910.6293.6664.7019.7357.7673.7967.8238.8485.8708.8907.9082.9236.9370.9484.9582.9664.9732.9788.9834.9871.9901.9925.9943.9957.9968.9977.9983.9988.9991.9994.9996.9997.04.5160.5557.5948.6331.6700.7054.7389.7704.7995.8264.8508.8729.8925.9099.9251.9382.9495.9591.9671.9738.9793.9838.9875.9904.9927.9945.9959.9969.9977.9984.9988.9992.9994.9996.9997.05.5199.5596.5987.6368.6736.7088.7422.7734.8023.8289.8531.8749.8944.9115.9265.9394.9505.9599.9678.9744.9798.9842.9878.9906.9929.9946.9960.9970.9978.9984.9989.9992.9994.9996.9997.06.5239.5636.6026.6406.6772.7123.7454.7764.8051.8315.8554.8770.8962.9131.9279.9406.9515.9608.9686.9750.9803.9846.9881.9909.9931.9948.9961.9971.9979.9985.9989.9992.9994.9996.9997.07.5279.5675.6064.6443.6808.7157.7486.7794.8078.8340.8577.8790.8980.9147.9292.9418.9525.9616.9693.9756.9808.9850.9884.9911.9932.9949.9962.9972.9979.9985.9989.9992.9995.9996.9997.08.5319.5714.6103.6480.6844.7190.7517.7823.8106.8365.8599.8810.8997.9162.9306.9429.9535.9625.9699.9761.9812.9854.9887.9913.9934.9951.9963.9973.9980.9986.9990.9993.9995.9996.9997.09.5359.5753.6141.6517.6879.7224.7549.7852.8133.8389.8621.8830.9015.9177.9319.9441.9545.9633.9706.9767.9817.9857.9890.9916.9936.9952.9964.9974.9981.9986.9990.9993.9995.9997.9998

Let z be a standard normal random variable with mean ? = 0 and standard deviation ? = 1. Use Table 3 in Appendix I to find the probability. (Round your answer to four decimal places.) To the left of 1.3

Let z be a standard normal random variable with mean ? = 0 and standard deviation ? = 1. Use Table 3 in Appendix I to find the probability. (Round your answer to four decimal places.) To the left of 1.3

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The probability that a randomly chosen student in a statistics class submits his/her homework on time is 0.12. There is 35 student in the class. Each student does his/her homework independently. What is the standard deviation of X, where X is the number of students who submit the homework on time?
Assume that adults have IQ scores that are normally distributed with a mean of mu equals 100 and a standard deviation sigma equals 20 . Find the probability that a randomly selected adult has an IQ less than 95 a. Find the z-score: z = nothing (round to 2 decimal places) b. Find the probability: nothing (use 4 decimal places)
A random sample of a population of size n = 36, find the prob that the mean is between 110 and 115. The pop u is 100, and the sd is 15.
Assume that the average weight of an NFL player is 245.7 lbs with a standard deviation of 34.5 lbs. The distribution of NFL weights is not normal. Suppose you took a random sample of 32 players. What is the probability that the sample average will be between 240 and 260 lbs? Round your answer to three decimal places, eg 0.192.
Assume that the average weight of an NFL player is 245.7 lbs with a standard deviation of 34.5 lbs. The distribution of NFL weights is not normal. Suppose you took a random sample of 32 players. What is the probability that the sample average will be less than 240 lbs? Round your answer to three decimal places, eg 0.192.
Draw a probability curve with your answer
The percent of fat calories that a person consumes each day is normally distributed with a mean of about 35 and a standard deviation of about ten. Suppose that 9 individuals are randomly chosen. Let X = average percent of fat calories. For the group of 9, find the probability that the average percent of fat calories consumed is more than six. (Round your answer to four decimal places.)
Assume that the average weight of an NFL player is 245.7 lbs with a standard deviation of 34.5 lbs. The distribution of NFL weights is not normal. Suppose you took a random sample of 32 players. What is the probability that the sample average will be between 240 and 252 lbs? Round your answer to three decimal places, eg 0.192.
Assume that the average weight of an NFL player is 245.7 lbs with a standard deviation of 34.5 lbs. The distribution of NFL weights is not normal. Suppose you took a random sample of 32 players. What is the probability that the sample average will be greater than 260 lbs? Round your answer to three decimal places, eg 0.192.
benk is 9.2 minutes with a standard deviation of The average waiting time for a drive in 2.6 minutes. Assume that the times A. Determine the probability, to 3 decimal places, t ustomer will have to wait less than 6 minutes. B. 20% of all customers will have to wait more than minutes. Round to 1 decimal place.
Find the indicated probability and interpret the result. From 1975 through 2020, the mean annual gain of the Dow Jones Industrial Average was 651. A random sample of 32 years is selected from this population. What is the probability that the mean gain for the sample was between 400 and 700? Assume o = 1540. The probability is (Round to four decimal places as needed.)
The mean percent of childhood asthma prevalence in 43 cities is 2.13%. A random sample of 32 of these cities is selected. What is the probability that the mean childhood asthma prevalence for the sample is greater than 2.5%? Interpret this probability. Assume that o = 1.34%. The probability is. (Round to four decimal places as needed.)