Z is a standard normal random variable. Use Excel to find Pr(Z < -1.31). Enter your answer as a decimal rounded to three decimal places, e.g. 0.268
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- Claim: Most adults would erase all of their personal information online if they could. A software firm survey of 446 randomly selected adults showed that 61% of them would erase all of their personal information online if they could. Find the value of the test statistic. The value of the test statistic is (Round to two decimal places as needed.)Cody took his first physics exam and scored an 80. The population mean for this exam is 70, and the standard deviation is 5. What is the probability of selecting a person with a score greater than Cody’s?Claim: Most adults would erase all of their personal information online if they could. A software firm survey of 619 randomly selected adults showed that 56% of them would erase all of their personal information online if they could. Find the value of the test statistic. The value of the test statistic is (Round to two decimal places as needed.)
- The accompanying table describes results from groups of 10 births from 10 different sets of parents. The random variable x represents the number of girls among 10 children. Use the range rule of thumb to determine whether 1 girl in 10 births is a significantly low number of girls. Click the icon to view the table. Use the range rule of thumb to identify a range of values that are not significant. The maximum value in this range is girls. (Round to one decimal place as needed.) *** Probability Distribution for x Number of Girls x 0 1 2 3 4 5 6 7 8 9 10 P(x) 0.002 0.012 0.043 0.115 0.203 0.234 0.198 0.115 0.038 0.011 0.029 D - XFind the p-value for a two-tailed test, where z= -1.68The mean height of women in a country (ages 20−29) is 64.1 inches. A random sample of 75 women in this age group is selected. What is the probability that the mean height for the sample is greater than 65 inches? Assume σ=2.58. The probability that the mean height for the sample is greater than 65 inches is
- The mean percent of childhood asthma prevalence in 43 cities is 2.13%. A random sample of 32 of these cities is selected. What is the probability that the mean childhood asthma prevalence for the sample is greater than 2.5%? Interpret this probability. Assume that o = 1.34%. The probability is. (Round to four decimal places as needed.)Claim: Most adults would erase all of their personal information online if they could. A software firm survey of 419 randomly selected adults showed that 62% of them would erase all of their personal information online if they could. Find the value of the test statistic. The value of the test statistic is (Round to two decimal places as needed.)X is a normally distributed random variable with mean 62 and standard deviation 13. What is the probability that X is between 36 and 88? Use the 0.68-0.95-0.997 rule and write your answer as a decimal.
- Claim: Most adults would erase all of their personal information online if they could. A software firm survey of 475 randomly selected adults showed that 65% of them would erase all of their personal information online if they could. Find the value of the test statistic. The value of the test statistic is (Round to two decimal places as needed.)The mean height of women in a country (ages 20−29) is 63.8 inches. A random sample of 55 women in this age group is selected. What is the probability that the mean height for the sample is greater than 65 inches? Assume σ=2.61.