Let x be a random variable representing the dividend yield of some stocks. Assume x has a normal distribution with o = 2.4%. A random sample of 10 stocks had an average of 5.38%. For the entire stock market the mean dividend yield i u = 4.7%. Does this data indicate that the %3D dividend yield of all stocks is higher than 4.7%? Use alpha = .01 %3D

Let x be a random variable representing the dividend yield of some stocks. Assume x has a normal distribution with o = 2.4%. A random sample of 10 stocks had an average of 5.38%. For the entire stock market the mean dividend yield i u = 4.7%. Does this data indicate that the %3D dividend yield of all stocks is higher than 4.7%? Use alpha = .01 %3D

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Find the Z score for which 80% of the distributions area lies between -z and z
Find -z and z such that 55% of the standard normal curve lies between –z and z.
A water footprint is a measure of the appropriation of fresh water. The per capita water footprint (in mega gallons) in a certain country for a recent year can be approximated by a normal distribution, as shown in the figure. (a) What water footprint represents the 84th percentile? (b) What water footprint represents the 26th percentile? (c) What water footprint represents the third quartile? 172 Mgal a-291 Mgal C 1.72 Mega galons 9.72 (a) The water footprint that represents the 84th percentile is (Round to two decimal places as needed.) Mgal.
The undergraduate grade point averages (UGPA) of students taking an admissions test in a recent year can be approximated by a normal distribution, as shown in the figure. (a) What is the minimum UGPA that would still place a student in the top 15% of UGPAS? (b) Between what two values does the middle 50% of the UGPAs lie? IN 2.52 μ= 3.26 o 0.15 3.26 Grade point average 4 X N
A population of values has a normal distribution with μ=200.6μ=200.6 and σ=20.8σ=20.8. You intend to draw a random sample of size n=236n=236.Find P17, which is the mean separating the bottom 17% means from the top 83% means.The mean = (Use 1 decimal place)
A food manufacturer claims that eating its new cereal as part of a daily diet lowers total blood cholesterol levels. The table shows the total blood cholesterol levels (in milligrams per deciliter of blood) of seven patients before eating the cereal and after one year of eating the cereal as part of their diets. Use technology to test the mean difference. Assume the samples are random and dependent, and the population is normally distributed. At α = 0.05, can you conclude that the new cereal lowers total blood cholesterol levels? Patient 1 2 3 4 5 6 7 Total Blood Cholesterol (Before) 205 220 240 235 250 270 230 Total Blood Cholesterol (After) 196 217 242 232 245 267 225 Let the blood cholesterol level before eating the cereal be population 1. Let the blood cholesterol level after eating the cereal be population 2. Identify the null and alternative hypotheses, where μμ₁ −μ₂. Choose the correct answer below. A. Ho: Hd #0 HA: Hd=0 B. Ho: Hd ≤0 HA: Md>0 C. Ho: Hd = 0 HA: Md #0 D. Ho: Hd 20…
Assume that adults have IQ scores that are normally distributed with a mean of μ=105 and a standard deviation σ=20. Find the probability that a randomly selected adult has an IQ between 93 and 117.
Titanium alloys have very high hardness. Adding small amounts of copper tends to improve their properties, such as hardness. In order to evaluate the effect of copper addition on hardness of titanium alloys, 10 random casts with 5% copper were made in an argon-arc melting furnace. The Rockwell hardness was determined for each of the casts. Then, the casts were subjected to high temperature (HT) and hardness was determined again in the second row. Assume hardness follows a normal distribution. Use the data below to answer the next three questions. 248 246 245 251 248 250 247 246 243 244 HARD5 HARD5HT 250 247 246 251 251 253 248 246 249 247 (a) Do the data provide evidence that high temperature increases the hardness of 5% copper alloys, on average? What is the distribution of the test statistic under the null hypothesis and the exact p-value? O t-distribution with df = 18; p-value = 0.0862 O t-distribution with df = 9; p-value = 0.00712 O t-distribution with df = 9; p-value = 0.00356 O…
The dean of a university estimates that the mean number of classroom hours per week for full-time faculty is 11.0. As a member of the student council, you want to test this claim. A random sample of the number of classroom hours for eight full-time faculty for one week is shown in the table below. At a=0.10, can you reject the dean's claim? Complete parts (a) through (d) below. Assume the population is normally distributed. 10.4 8.2 8.8 12.6 13.1 6.1 9.90 11.3 (a) Write the claim mathematically and identify Ho and Ha Which of the following correctly states Ho and H₂? Ο Α. Ho: με 11.0 H₂>11.0 O D. Ho: 11.0 H: ≤11.0 A O A. Fail to reject Ho because the P-value is greater than the significance level. OB. Reject H, because the P-value is greater than the significance level. OC. Reject Ho because the P-value is less than the significance level. OD. Fail to reject Ho because the P-value is less than the significance level. (d) Interpret the decision in the context of the original claim. O A.…
A population of values has a normal distribution with μ=204.6μ=204.6 and σ=17σ=17. You intend to draw a random sample of size n=92n=92.Find P67, which is the score separating the bottom 67% scores from the top 33% scores.P67 (for single values) = IncorrectFind P67, which is the mean separating the bottom 67% means from the top 33% means.P67 (for sample means) = Enter your answers as numbers accurate to 1 decimal place. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
A population of values has a normal distribution with μ=248.4μ=248.4 and σ=23.6σ=23.6. You intend to draw a random sample of size n=32n=32.Find P18, which is the score separating the bottom 18% scores from the top 82% scores.P18 (for single values) = Find P18, which is the mean separating the bottom 18% means from the top 82% means.P18 (for sample means) = Enter your answers as numbers accurate to 1 decimal place.************NOTE************ round your answer to ONE digit after the decimal point! ***********Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
The undergraduate grade point averages (UGPA) of students taking an admissions test in a recent year can be approximated by a normal distribution, as shown in the figure. (a) What is the minimum UGPA that would still place a student in the top 15% of UGPAS? (b) Between what two values does the middle 50% of the UGPAS lie? H=3.26 G=0.16 3.26 2.52 Grade point average (a) The minimum UĞPA that would still place a student in the top 15% of UGPAS is (Round to two decimal places as needed.) (b) The middle 50% of UGPAS lies between on the low end and on the high end. (Round to two decimal places as needed.)