The undergraduate grade point averages​ (UGPA) of students taking an admissions test in a recent year can be approximated by a normal​ distribution, as shown in the figure.   ​(a) What is the minimum UGPA that would still place a student in the top 1​5%of​ UGPAs? ​(b) Between what two values does the middle 50​% of the UGPAs​ lie?   Mean: 3.30 Standart deviation: 0.18

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The undergraduate grade point averages​ (UGPA) of students taking an admissions test in a recent year can be approximated by a normal​ distribution, as shown in the figure.
 
​(a) What is the minimum UGPA that would still place a student in the top 1​5%of​ UGPAs?
​(b) Between what two values does the middle 50​% of the UGPAs​ lie?
 
Mean: 3.30
Standart deviation: 0.18
 
Grade point average: 2.6    3.30     4
Expert Solution
Step 1

Z = x-μσ~N(0,1)

_____________________________

Excel function =NORMSINV() is used , 

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