A random variable X follows a Binomia distribution with n=209 and p=0.65. Using the Normal approximation of the Binomial distribution, calculate the continuity corrected Z-score for observing a number of successes greater than or equal to 126. You do not have to estimate the probability. (Hint: the continuity correction is an adjustment included in the calculation to reflect that we are estimating probability for a discrete distribution with a continuous distribution. Enter your answer to two decimal places.

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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A random variable X follows a Binomial
distribution with n=209 and p=0.65.
Using the Normal approximation of the
Binomial distribution, calculate the
continuity corrected Z-score for
observing a number of successes
greater than or equal to 126. You do
not have to estimate the probability.
(Hint: the continuity correction is an
adjustment included in the calculation
to reflect that we are estimating
probability for a discrete distribution
with a continuous distribution. Enter
your answer to two decimal places.
Transcribed Image Text:A random variable X follows a Binomial distribution with n=209 and p=0.65. Using the Normal approximation of the Binomial distribution, calculate the continuity corrected Z-score for observing a number of successes greater than or equal to 126. You do not have to estimate the probability. (Hint: the continuity correction is an adjustment included in the calculation to reflect that we are estimating probability for a discrete distribution with a continuous distribution. Enter your answer to two decimal places.
Suppose that a test has a distribution
that is normal with a mean of 542.6
and a standard deviation of 95.6.
Calculate the exam score that
corresponds to the 90th percentile.
Enter your answer to the nearest
integer. Hint: The 90th percentile of
the standard normal curve is z = 1.282.
Transcribed Image Text:Suppose that a test has a distribution that is normal with a mean of 542.6 and a standard deviation of 95.6. Calculate the exam score that corresponds to the 90th percentile. Enter your answer to the nearest integer. Hint: The 90th percentile of the standard normal curve is z = 1.282.
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