Fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean ? = 26.6 kilograms and standard deviation ? = 3.4 kilograms. Let x be the weight of a fawn in kilograms. (g) If a fawn weighs 14 kilograms, would you say it is an unusually small animal? Explain using z values and the figure above. A. Yes. This weight is 3.71 standard deviations below the mean; 14 kg is an unusually low weight for a fawn. B. Yes. This weight is 1.85 standard deviations below the mean; 14 kg is an unusually low weight for a fawn. C. No. This weight is 3.71 standard deviations below the mean; 14 kg is a normal weight for a fawn. D. No. This weight is 3.71 standard deviations above the mean; 14 kg is an unusually high weight for a fawn. E. No. This weight is 1.85 standard deviations above the mean; 14 kg is an unusually high weight for a fawn. (h) If a fawn is unusually large, would you say that the z value for the weight of the fawn will be close to 0, −2, or 3? Explain. A. It would have a negative z, such as −2. B. It would have a large positive z, such as 3. C. It would have a z of 0.
Fawns between 1 and 5 months old have a body weight that is approximately
(g) If a fawn weighs 14 kilograms, would you say it is an unusually small animal? Explain using z values and the figure above.
A. Yes. This weight is 3.71 standard deviations below the mean; 14 kg is an unusually low weight for a fawn.
B. Yes. This weight is 1.85 standard deviations below the mean; 14 kg is an unusually low weight for a fawn.
C. No. This weight is 3.71 standard deviations below the mean; 14 kg is a normal weight for a fawn.
D. No. This weight is 3.71 standard deviations above the mean; 14 kg is an unusually high weight for a fawn.
E. No. This weight is 1.85 standard deviations above the mean; 14 kg is an unusually high weight for a fawn.
(h) If a fawn is unusually large, would you say that the z value for the weight of the fawn will be close to 0, −2, or 3? Explain.
A. It would have a negative z, such as −2.
B. It would have a large positive z, such as 3.
C. It would have a z of 0.
![The Standard Normal Distribution
(u = 0, o = 1)
-3
-2
2
3
68% of area
95% of area
99.7% of area](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fda8bfc36-553b-49bb-bf15-c6d3e6502208%2F7aae609f-6073-4d22-a004-cf2114ec4447%2Fiiuy0dp_processed.png&w=3840&q=75)
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